The current I drawn from the 5 V source will be
a) |
0.33A |
b) |
0.5A |
c) |
0.67A |
d) |
0.17A |
The current I drawn from the 5 V source will be
a) |
0.33A |
b) |
0.5A |
c) |
0.67A |
d) |
0.17A |
(b)
The given circuit can be redrawn as
Which is a balanced Wheatstone’s bridge and hence, no current flows in the centre resistor, so equivalent circuit would be as shown below.
So,