Two policemen, $\mathrm{A}$ and $\mathrm{B}$, fire once each at the same time at an escaping convict. The probability that A hits the convict is three times the probability that B hits the convict. If the probability of the convict not getting injured is $0.5,$ the probability that $\mathrm{B}$ hits the convict is

(A) 0.14

(B) 0.22

(C) 0.33

(D) 0.40

Two policemen, $\mathrm{A}$ and $\mathrm{B}$, fire once each at the same time at an escaping convict. The probability that A hits the convict is three times the probability that B hits the convict. If the probability of the convict not getting injured is $0.5,$ the probability that $\mathrm{B}$ hits the convict is

(A) 0.14

(B) 0.22

(C) 0.33

(D) 0.40

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