Two policemen, $\mathrm{A}$ and $\mathrm{B}$, fire once each at the same time at an escaping convict. The probability that A hits the convict is three times the probability that B hits the convict. If the probability of the convict not getting injured is $0.5,$ the probability that $\mathrm{B}$ hits the convict is
(A) 0.14
(B) 0.22
(C) 0.33
(D) 0.40

Question ID - 157408 | SaraNextGen Top Answer

Two policemen, $\mathrm{A}$ and $\mathrm{B}$, fire once each at the same time at an escaping convict. The probability that A hits the convict is three times the probability that B hits the convict. If the probability of the convict not getting injured is $0.5,$ the probability that $\mathrm{B}$ hits the convict is
(A) 0.14
(B) 0.22
(C) 0.33
(D) 0.40