In a Young’s double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = 500 mm is incident on the slits. The total number of bright fringes that are observed in the angular range −30° ≤ θ ≤ 30° is
Question ID - 50107 | Top Ranker Answer | SaraNextGen In a Young’s double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = 500 mm is incident on the slits. The total number of bright fringes that are observed in the angular range −30° ≤ θ ≤ 30° is
In a Young’s double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ = 500 mm is incident on the slits. The total number of bright fringes that are observed in the angular range −30° ≤ θ ≤ 30° is
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Pam difference
dsinθ = nλ
where d= separation of slits
λ = wave length
n= no. of maximas
0.32 × 10−3 sin 30 = n = 500 × 10−9
N= 320
Hence total no. of maxmias observed in angular range −30° ≤ θ ≤ 30° is
Maximas = 320 + 1 + 320 = 641
