A rod of mass ‘M’ and length ‘2L’ is suspended at its middle by a wire. It exhibits torsional oscillations; if two masses each of ‘m’ are attached at distance ‘L/2’ from its centre on both sides, it reduces the oscillation frequency by 20% The value of ratio m/M is close to:

A rod of mass ‘M’ and length ‘2L’ is suspended at its middle by a wire. It exhibits torsional oscillations; if two masses each of ‘m’ are attached at distance ‘L/2’ from its centre on both sides, it reduces the oscillation frequency by 20% The value of ratio m/M is close to:

1 Answer

127 votes

Frequency of torsonal oscillations is given by

f=

f_{1} =

f _{2}=

f_{2} = 0.8 f_{1}

= 0.375

127 votes

127