A rod of mass ‘M’ and length ‘2L’ is suspended at its middle by a wire. It exhibits torsional oscillations; if two masses each of ‘m’ are attached at distance ‘L/2’ from its centre on both sides, it reduces the oscillation frequency by 20% The value of ratio m/M is close to:
Question ID - 50114 | SaraNextGen Top Answer A rod of mass ‘M’ and length ‘2L’ is suspended at its middle by a wire. It exhibits torsional oscillations; if two masses each of ‘m’ are attached at distance ‘L/2’ from its centre on both sides, it reduces the oscillation frequency by 20% The value of ratio m/M is close to:
A rod of mass ‘M’ and length ‘2L’ is suspended at its middle by a wire. It exhibits torsional oscillations; if two masses each of ‘m’ are attached at distance ‘L/2’ from its centre on both sides, it reduces the oscillation frequency by 20% The value of ratio m/M is close to:
1 Answer
127 votes
Answer Key / Explanation : (0.375) -
Frequency of torsonal oscillations is given by
f= 
f1 = 
f 2= 
f2 = 0.8 f1
= 0.375
127 votes
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127