Last Updated On 16-03-2023 - By Jeesha Sara
An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10−29 C.m. What is the potential energy of the electric dipole?
|
a. |
− 9 × 10−20 J |
b. |
− 7 × 10−27 J |
|
c. |
− 10 × 10−29 J |
d. |
− 20 × 10−18 J |
Question ID - 50343 :- An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10−29 C.m. What is the potential energy of the electric dipole?
a.
− 9 × 10−20 J
b.
− 7 × 10−27 J
c.
− 10 × 10−29 J
d.
− 20 × 10−18 J
An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10−29 C.m. What is the potential energy of the electric dipole?
|
a. |
− 9 × 10−20 J |
b. |
− 7 × 10−27 J |
|
c. |
− 10 × 10−29 J |
d. |
− 20 × 10−18 J |
U = − 
= −PE cos
= − (10−29) (103) cos 45
= −0.707 x 10−26 J
= − 7 x 10−27 J.
Next Question :
A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of 1 rad/s and amplitude of 10−2 m. The relative change in the angular frequency of the pendulum is best given by
|
a. |
10−3 rad/s |
b. |
10−1 rad/s |
|
c. |
1 rad/s |
d. |
10−5 rad/s |
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