An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10^{−29} C.m. What is the potential energy of the electric dipole?

a. |
− 9 × 10 |
b. |
− 7 × 10 |

c. |
− 10 × 10 |
d. |
− 20 × 10 |

An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is 10^{−29} C.m. What is the potential energy of the electric dipole?

a. |
− 9 × 10 |
b. |
− 7 × 10 |

c. |
− 10 × 10 |
d. |
− 20 × 10 |

1 Answer - 5876 Votes

3537

U = −

= −PE cos

= − (10^{−}^{29}) (10^{3}) cos 45

= −0.707 x 10^{−}^{26 }J

= − 7 x 10^{−}^{27} J.