A thin convex lens L (refractive index=1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA=18 cm, its real inverted image is formed at A itself, as shown in the figure. When a liquid of refractive index 
is put between the lens and the mirror, the pin has to be moved to A’, such that OA’=27 cm, to gets its inverted real image at A’ itself. The value of 
will be
(a)
(b)
(c)
(d)
A thin convex lens L (refractive index=1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA=18 cm, its real inverted image is formed at A itself, as shown in the figure. When a liquid of refractive index is put between the lens and the mirror, the pin has to be moved to A’, such that OA’=27 cm, to gets its inverted real image at A’ itself. The value of will be
(a)
(b)
(c)
(d)
Question ID - 51303 | SaraNextGen Top Answer
A thin convex lens L (refractive index=1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA=18 cm, its real inverted image is formed at A itself, as shown in the figure. When a liquid of refractive index is put between the lens and the mirror, the pin has to be moved to A’, such that OA’=27 cm, to gets its inverted real image at A’ itself. The value of will be
(a)
(b)
(c)
(d)
|
A thin convex lens L (refractive index=1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA=18 cm, its real inverted image is formed at A itself, as shown in the figure. When a liquid of refractive index |
|||
|
(a) |
|
(b) |
|
|
(c) |
|
(d) |
|
fL=18cm
=0.5
⇒ R=18cm
=(
=
− 
=
⇒ 2=3(2−
=6−3
⇒
=