Question 3.10:
If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?
Answer:
I = 0.5 A
t = 2 hours = 2 × 60 × 60 s = 7200 s
Thus, Q = It
= 0.5 A × 7200 s
= 3600 C
We know that number of electrons.
Then,
Hence, number of electrons will flow through the wire.
Question 3.11:
Suggest a list of metals that are extracted electrolytically.
Answer:
Metals that are on the top of the reactivity series such as sodium, potassium, calcium, lithium, magnesium, aluminium are extracted electrolytically.
Question 3.12:
What is the quantity of electricity in coulombs needed to reduce 1 mol of
? Consider the reaction:
Answer:
The given reaction is as follows:
Therefore, to reduce 1 mole of , the required quantity of electricity will be:
=6 F
= 6 × 96487 C
= 578922 C