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Page No 117: - Chapter 4 Chemical Kinetics Exercise Solutions class 12 ncert solutions Chemistry - SaraNextGen [2024-2025]


Question 4.1:

From the rate expression for the following reactions, determine their order of reaction and the dimensions of the rate constants.

(i) 3 NO(g) → N2O (g) Rate = k[NO]2

(ii) H2O(aq) + 3 I− (aq) + 2 H+ → 2 H2O (l) + https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m4c7b31ab.gif  Rate = k[H2O2][I]

(iii) CH3CHO(g) → CH4(g) + CO(g) Rate = [CH3CHO]3/2

(iv) C2H5Cl(g) → C2H4(g) + HCl(g) Rate = [C2H5Cl]

Answer:

(i) Given rate = [NO]2

Therefore, order of the reaction = 2

Dimension of https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m3b22fd6b.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m721084d0.gif

(ii) Given rate = [H2O2] [I]

Therefore, order of the reaction = 2

Dimension of https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_795ae02.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m10a6b4b2.gif

(iii) Given rate = [CH3CHO]3/2

Therefore, order of reaction = https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m47d40970.gif

Dimension of https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_71de0a04.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_1bd21519.gif

(iv) Given rate = [C2H5Cl]

Therefore, order of the reaction = 1

Dimension of https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_6629c3a8.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6329/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m4d709495.gif

Question 4.2:

For the reaction:

2A + B → A2B

the rate = k[A][B]2 with k = 2.0 × 10−6 mol−2 L2 s−1. Calculate the initial rate of the reaction when [A] = 0.1 mol L−1, [B] = 0.2 mol L−1. Calculate the rate of reaction after [A] is reduced to 0.06 mol L−1.

Answer:

The initial rate of the reaction is

Rate = [A][B]2

= (2.0 × 10−6 mol−2 L2 s−1) (0.1 mol L−1) (0.2 mol L−1)2

= 8.0 × 10−9 mol−2 L2 s−1

When [A] is reduced from 0.1 mol L−1 to 0.06 mol−1, the concentration of A reacted = (0.1 − 0.06) mol L−1 = 0.04 mol L−1

Therefore, concentration of B reacted https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6331/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m4019195.gif = 0.02 mol L−1

Then, concentration of B available, [B] = (0.2 − 0.02) mol L−1

= 0.18 mol L−1

After [A] is reduced to 0.06 mol L−1, the rate of the reaction is given by,

Rate = [A][B]2

= (2.0 × 10−6 mol−2 L2 s−1) (0.06 mol L−1) (0.18 mol L−1)2

= 3.89 mol L−1 s−1

Question 4.3:

The decomposition of NH3 on platinum surface is zero order reaction. What are the rates of production of N2 and H2 if = 2.5 × 10−4 mol−1 L s−1?

Answer:

The decomposition of NH3 on platinum surface is represented by the following equation.

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6332/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m60473d8e.gif

Therefore,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6332/NS_14-11-08_Utpal_12_Chemistry_4_30_html_350a4e76.gif

However, it is given that the reaction is of zero order.

Therefore,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6332/NS_14-11-08_Utpal_12_Chemistry_4_30_html_1efbb932.gif

Therefore, the rate of production of N2 is

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6332/NS_14-11-08_Utpal_12_Chemistry_4_30_html_483a3837.gif

And, the rate of production of H2 is

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6332/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m52c63472.gif

= 7.5 × 10−4 mol L−1 s−1

Question 4.4:

The decomposition of dimethyl ether leads to the formation of CH4, H2 and CO and the reaction rate is given by

Rate = [CH3OCH3]3/2

The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e.,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6333/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m2469a1fb.gif

If the pressure is measured in bar andtime in minutes, then what are the units of rate and rate constants?

Answer:

If pressure is measured in bar and time in minutes, then

Unit of rate = bar min−1

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6333/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m2469a1fb.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6333/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m3784d290.gif

Therefore, unit of rate constantshttps://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6333/NS_14-11-08_Utpal_12_Chemistry_4_30_html_499cfced.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6333/NS_14-11-08_Utpal_12_Chemistry_4_30_html_m2f900d95.gif

Question 4.5:

Mention the factors that affect the rate of a chemical reaction.

Answer:

The factors that affect the rate of a reaction are as follows.

(i) Concentration of reactants (pressure in case of gases)

(ii) Temperature

(iii) Presence of a catalyst

Also Read : Page-No-118:-Chapter-4-Chemical-Kinetics-Exercise-Solutions-class-12-ncert-solutions-Chemistry

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