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Page No 103: - Chapter 4 Chemical Kinetics Intext Solutions class 12 ncert solutions Chemistry - SaraNextGen [2024]


Question 4.3:

For a reaction, A + B → Product; the rate law is given by,https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6316/NCERT(INTEXT)_13-11-08_Utpal_12_Chemistry_4_9_html_72be5927.gif . What is the order of the reaction?

Answer:

The order of the reactionhttps://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6316/NCERT(INTEXT)_13-11-08_Utpal_12_Chemistry_4_9_html_3d801889.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/263/6316/NCERT(INTEXT)_13-11-08_Utpal_12_Chemistry_4_9_html_29e9d4f5.gif

= 2.5

Question 4.4:

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

Answer:

The reaction X → Y follows second order kinetics.

Therefore, the rate equation for this reaction will be:

Rate = k[X]2 (1)

Let [X] = a mol L−1, then equation (1) can be written as:

Rate1 = k .(a)2

ka2

If the concentration of X is increased to three times, then [X] = 3a mol L−1

Now, the rate equation will be:

Rate = k (3a)2

= 9(ka2)

Hence, the rate of formation will increase by 9 times.

Also Read : Page-No-111:-Chapter-4-Chemical-Kinetics-Intext-Solutions-class-12-ncert-solutions-Chemistry

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