Question 7.7:
Bond angle in is higher than that in PH3. Why?
Answer:
In PH3, P is sp3 hybridized. Three orbitals are involved in bonding with three hydrogen atoms and the fourth one contains a lone pair. As lone pair-bond pair repulsion is stronger than bond pair-bond pair repulsion, the tetrahedral shape associated with sp3 bonding is changed to pyramidal. PH3 combines with a proton to form in which the lone pair is absent. Due to the absence of lone pair in , there is no lone pair-bond pair repulsion. Hence, the bond angle in is higher than the bond angle in PH3.
Question 7.8:
What happens when white phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO2?
Answer:
White phosphorous dissolves in boiling NaOH solution (in a CO2 atmosphere) to give phosphine, PH3.