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Page No 174: - Chapter 12 Sound class 9 ncert solutions Science - SaraNextGen [2024]


Question 1:

What is sound and how is it produced?

Answer:

Sound is produced by vibration. When a body vibrates, it forces the neighbouring particles of the medium to vibrate. This creates a disturbance in the medium, which travels in the form of waves. This disturbance, when reaches the ear, produces sound.

 

 

Question 2:

Describe with the help of a diagram, how compressions and rarefactions are produced in air near a source of sound.

Answer:

When a vibrating body moves forward, it creates a region of high pressure in its vicinity. This region of high pressure is known as compressions. When it moves backward, it creates a region of low pressure in its vicinity. This region is known as a rarefaction. As the body continues to move forward and backwards, it produces a series of compressions and rarefactions (as shown in the following figure).

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1295/Chapter%2012_html_m65a5d975.jpg

 

Question 3:

Cite an experiment to show that sound needs a material medium for its propagation.

Answer:

Take an electric bell and hang this bell inside an empty bell-jar fitted with a vacuum pump (as shown in the following figure).

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1296/Chapter%2012_html_48046a49.jpg

Initially, one can hear the sound of the ringing bell. Now, pump out some air from the bell-jar using the vacuum pump. It will be observed that the sound of the ringing bell decreases. If one keeps on pumping the air out of the bell-jar, then at one point, the glass-jar will be devoid of any air. At this moment, no sound can be heard from the ringing bell although one can see that the prong of the bell is still vibrating. When there is no air present inside, we can say that a vacuum is produced. Sound cannot travel through vacuum. This shows that sound needs a material medium for its propagation.

 

Question 4:

Why is sound wave called a longitudinal wave?

Answer:

The vibration of the medium that travels along or parallel to the direction of the wave is called a longitudinal wave. In a sound wave, the particles of the medium vibrate in the direction parallel to the direction of the propagation of disturbance. Hence, a sound wave is called a longitudinal wave.

 

 

Question 5:

Which characteristics of the sound helps you to identify your friend by his voice while sitting with others in a dark room?

Answer:

Quality of sound is that characteristic which helps us identify a particular person. Sound produced by two persons may have the same pitch and loudness, but the quality of the two sounds will be different.

 

 

Question 6:

Flash and thunder are produced simultaneously. But thunder is heard a few seconds after the flash is seen, why?

Answer:

The speed of sound https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1301/Chapter%2012_html_50397ee9.gif  is less than the speed of lighthttps://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1301/Chapter%2012_html_75dc264.gif . Sound of thunder takes more time to reach the Earth as compared to light. Hence, a flash is seen before we hear a thunder.

 

 

Question 7:

A person has a hearing range from 20 Hz to 20 kHz. What are the typical wavelengths of sound waves in air corresponding to these two frequencies? Take the speed of sound in air as 344 m s−1.

Answer:

For a sound wave,

Speed = Wavelength × Frequency

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1303/Chapter%2012_html_m57c0bd5e.gif

Given that the speed of sound in air = 344 m/s

(i) For, https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1303/Chapter%2012_html_m5aaabc6e.gif  = 20 Hz

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1303/Chapter%2012_html_m5c67b7d1.gif

(ii) For, https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1303/Chapter%2012_html_7203767f.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1303/Chapter%2012_html_458cce3d.gif

Hence, for humans, the wavelength range for hearing is 0.0172 m to 17.2 m.

 

Question 8:

Two children are at opposite ends of an aluminium rod. One strikes the end of the rod with a stone. Find the ratio of times taken by the sound wave in air and in aluminium to reach the second child.

Answer:

Let the length of the aluminium rod be d.

Speed of sound wave in aluminium at 25°C, https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1305/Chapter%2012_html_18a209b9.gif

Therefore, time taken by the sound wave to reach the other end,

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1305/Chapter%2012_html_m9d3d475.gif

Speed of sound wave in air at 25°C, https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1305/Chapter%2012_html_221f91e2.gif

Therefore, time taken by sound wave to reach the other end,

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1305/Chapter%2012_html_6ebefa5d.gif

The ratio of time taken by the sound wave in air and aluminium: https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1305/Chapter%2012_html_m78c49f60.gif

 

 

Question 9:

The frequency of a source of sound is 100 Hz. How many times does it vibrate in a minute?

Answer:

Frequency is defined as the number of oscillations per second. It is given by the relation:

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1306/Chapter%2012_html_m7ddf9832.gif

Number of oscillations = Frequency × Total time

Given, Frequency of sound = 100 Hz

Total time = 1 min = 60 s

Number of oscillations/Vibrations = 100 × 60 = 6000

Hence, the source vibrates 6000 times in a minute, producing a frequency of 100 Hz.

 

Question 10:

Does sound follow the same laws of reflection as light does? Explain.

Answer:

Sound follows the same laws of reflection as light does. The incident sound wave and the reflected sound wave make the same angle with the normal to the surface at the point of incidence. Also, the incident sound wave, the reflected sound wave, and the normal to the point of incidence all lie in the same plane.

 

 

Question 11:

When a sound is reflected from a distant object, an echo is produced. Let the distance between the reflecting surface and the source of sound production remains the same. Do you hear echo sound on a hotter day?

Answer:

An echo is heard when the time interval between the original sound and the reflected sound is at least 0.1 s. The speed of sound in a medium increases with an increase in temperature. Hence, on a hotter day, the time interval between the original sound and the reflected sound will decrease. Therefore, an echo can be heard only if the time interval between the original sound and the reflected sound is greater than 0.1 s.

 

 

Question 12:

Give two practical applications of reflection of sound waves.

Answer:

(i) Reflection of sound is used to measure the distance and speed of underwater objects. This method is known as SONAR.

(ii) Working of a stethoscope is also based on reflection of sound. In a stethoscope, the sound of the patient’s heartbeat reaches the doctor’s ear by multiple reflection of sound.

 

 

Question 13:

A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 m s−2 and speed of sound = 340 m s−1.

Answer:

Height of the tower, s = 500 m

Velocity of sound, v = 340 m s−1

Acceleration due to gravity, g = 10 m s−2

Initial velocity of the stone, u = 0 (since the stone is initially at rest)

Time taken by the stone to fall to the base of the tower, t1

According to the second equation of motion:

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1315/Chapter%2012_html_m4fc98686.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1315/Chapter%2012_html_27028c4a.gif

Now, time taken by the sound to reach the top from the base of the tower, https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1315/Chapter%2012_html_m60fdc014.gif

Therefore, the splash is heard at the top after time, t

Where, https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1315/Chapter%2012_html_3ab04e7f.gif

 

Question 14:

A sound wave travels at a speed of 339 m s−1. If its wavelength is 1.5 cm, what is the frequency of the wave? Will it be audible?

Answer:

Speed of sound, v = 339 m s−1

Wavelength of sound, https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1316/Chapter%2012_html_m11cc021f.gif = 1.5 cm = 0.015 m

Speed of sound = Wavelength × Frequency

https://img-nm.mnimgs.com/img/study_content/curr/1/9/8/124/1316/Chapter%2012_html_m63a56ca.gif

The frequency range of audible sound for humans lies between 20 Hz to 20,000 Hz. Since the frequency of the given sound is more than 20,000 Hz, it is not audible.

Also Read : Page-No-175:-Chapter-12-Sound-class-9-ncert-solutions-Science

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