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Exercise 4.4 - Chapter 4 Determinants class 12 ncert solutions Maths - SaraNextGen [2024]


Question 1:

Write Minors and Cofactors of the elements of following determinants:

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6506/Chapter%204_html_4c1d6bdf.gif  (ii) https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6506/Chapter%204_html_7163090e.gif

Answer:

(i) The given determinant ishttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6506/Chapter%204_html_4c1d6bdf.gif .

Minor of element aij is Mij.

∴M11 = minor of element a11 = 3

M12 = minor of element a12 = 0

M21 = minor of element a21 = −4

M22 = minor of element a22 = 2

Cofactor of aij is Aij = (−1)i + j Mij.

∴A11 = (−1)1+1 M11 = (−1)2 (3) = 3

A12 = (−1)1+2 M12 = (−1)3 (0) = 0

A21 = (−1)2+1 M21 = (−1)3 (−4) = 4

A22 = (−1)2+2 M22 = (−1)4 (2) = 2

(ii) The given determinant ishttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6506/Chapter%204_html_7163090e.gif .

Minor of element aij is Mij.

∴M11 = minor of element a11 d

M12 = minor of element a12 b

M21 = minor of element a21 c

M22 = minor of element a22 a

Cofactor of aij is Aij = (−1)i + j Mij.

∴A11 = (−1)1+1 M11 = (−1)2 (d) = d

A12 = (−1)1+2 M12 = (−1)3 (b) = −b

A21 = (−1)2+1 M21 = (−1)3 (c) = −c

A22 = (−1)2+2 M22 = (−1)4 (a) = a

Question 2:

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_3a2f2c7d.gif  (ii) https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_m2c718806.gif

Answer:

(i) The given determinant ishttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_3a2f2c7d.gif .

By the definition of minors and cofactors, we have:

M11 = minor of a11https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_60e063c8.gif

M12 = minor of a12https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_2cab0469.gif

M13 = minor of a13 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_3b4b8277.gif

M21 = minor of a21 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_2cab0469.gif

M22 = minor of a22 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_60e063c8.gif

M23 = minor of a23 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_m1839b8f4.gif

M31 = minor of a31https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_mcb43f5.gif

M32 = minor of a32 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_m1839b8f4.gif

M33 = minor of a33 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_60e063c8.gif

A11 = cofactor of a11= (−1)1+1 M11 = 1

A12 = cofactor of a12 = (−1)1+2 M12 = 0

A13 = cofactor of a13 = (−1)1+3 M13 = 0

A21 = cofactor of a21 = (−1)2+1 M21 = 0

A22 = cofactor of a22 = (−1)2+2 M22 = 1

A23 = cofactor of a23 = (−1)2+3 M23 = 0

A31 = cofactor of a31 = (−1)3+1 M31 = 0

A32 = cofactor of a32 = (−1)3+2 M32 = 0

A33 = cofactor of a33 = (−1)3+3 M33 = 1

(ii) The given determinant ishttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_m2c718806.gif .

By definition of minors and cofactors, we have:

M11 = minor of a11https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_4f458875.gif

M12 = minor of a12https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_m74174ac.gif

M13 = minor of a13 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_m4020840d.gif

M21 = minor of a21 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_5a462540.gif

M22 = minor of a22 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_f54608.gif

M23 = minor of a23 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_75906887.gif

M31 = minor of a31https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_m159f40e3.gif

M32 = minor of a32 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_61b799fe.gif

M33 = minor of a33 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6507/Chapter%204_html_m4b6f0e09.gif

A11 = cofactor of a11= (−1)1+1 M11 = 11

A12 = cofactor of a12 = (−1)1+2 M12 = −6

A13 = cofactor of a13 = (−1)1+3 M13 = 3

A21 = cofactor of a21 = (−1)2+1 M21 = 4

A22 = cofactor of a22 = (−1)2+2 M22 = 2

A23 = cofactor of a23 = (−1)2+3 M23 = −1

A31 = cofactor of a31 = (−1)3+1 M31 = −20

A32 = cofactor of a32 = (−1)3+2 M32 = 13

A33 = cofactor of a33 = (−1)3+3 M33 = 5

Question 3:

Using Cofactors of elements of second row, evaluatehttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6510/Chapter%204_html_4012cc43.gif .

Answer:

The given determinant ishttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6510/Chapter%204_html_33225305.gif .

We have:

M21 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6510/Chapter%204_html_m60011a16.gif

∴A21 = cofactor of a21 = (−1)2+1 M21 = 7

M22 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6510/Chapter%204_html_m1894bee1.gif

∴A22 = cofactor of a22 = (−1)2+2 M22 = 7

M23 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6510/Chapter%204_html_m31bb8baf.gif

∴A23 = cofactor of a23 = (−1)2+3 M23 = −7

We know that Δ is equal to the sum of the product of the elements of the second row with their corresponding cofactors.

∴Δ = a21A21 + a22A22 + a23A23 = 2(7) + 0(7) + 1(−7) = 14 − 7 = 7

Question 4:

Using Cofactors of elements of third column, evaluatehttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6511/Chapter%204_html_m2103290e.gif

Answer:

The given determinant ishttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6511/Chapter%204_html_m5bc7a10c.gif .

We have:

M13 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6511/Chapter%204_html_m6642f1eb.gif

M23 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6511/Chapter%204_html_6d53621e.gif

M33 https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6511/Chapter%204_html_11b50959.gif

∴A13 = cofactor of a13 = (−1)1+3 M13 = (z − y)

A23 = cofactor of a23 = (−1)2+3 M23 = − (z − x) = (x − z)

A33 = cofactor of a33 = (−1)3+3 M33 = (y − x)

We know that Δ is equal to the sum of the product of the elements of the second row with their corresponding cofactors.

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6511/Chapter%204_html_m7f475413.gif

Hence, https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6511/Chapter%204_html_7f498b9.gif

Question 5:

If https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6512/Chapter%204_html_m4a2fd7e0.gif  and Aij is Cofactors of aij, then value of Δ is given by

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/233/6512/Chapter%204_html_c4712c.gif

Answer:

Answer: D

We know that:

Δ = Sum of the product of the elements of a column (or a row) with their corresponding cofactors

∴Δ = a11A11 + a21A21 + a31A31

Hence, the value of Δ is given by the expression given in alternative D.

The correct Answer is D.

Also Read : Exercise-4.5-Chapter-4-Determinants-class-12-ncert-solutions-Maths

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