Exercise 1.4 - Chapter 1 Numbers Term 1 6th Maths Guide Samacheer Kalvi Solutions - SaraNextGen [2024-2025]

Updated By SaraNextGen

On April 24, 2024, 11:35 AM

Ex 1.4
Question $1 .$
Fill in the blanks.
(i) The nearest 100 of 843 is
(ii) The nearest 1000 of 756 is
(iii) The nearest 10,000 of 85654 is
Solution:
(i) 800 .
The digit in tens place is $4<5$
(ii) 1000 .
The digit in hundred places is $7 \geq 5$
(iii) 90,000 .
The digit in a thousand places is $5 \geq 5$

Question $2 .$
Say True or False.
(i) 8567 is rounded off as 8600 to the nearest 10 .
(ii) 139 is rounded off as 100 to the nearest 100 .
(iii) $1,70,51,972$ is rounded off as $1,70,00,000$ to the nearest lakh.
Solution:
(i) False
(ii) True
(iii) False

Question $3 .$
Round off the following to the given nearest place.
(i) 4065 ; hundred
(ii) 44,555 ; thousand

(iii) 86943 ; ten thousand
(iv) $50,81,739$; lakh
(v) $33,75,98,482$; Ten crore
Solution:
(i) We have to round off 4065 to hundreds
The place value is a hundred
The digit in hundreds place is 0
The digit to the right is $6>5$
Adding 1 to $0 \Rightarrow 0+1=1$
Changing the digits to the right of 41 to zeros
$4065 \simeq 4100 \Rightarrow 4100$
(ii) To round off 44555 to thousands
The digit in the thousands place is 4
digit to the right is $5=5$.
Adding 1 to the thousand place value digit $4 \Rightarrow 4+1=5$
Changing the digits to the right of 45 to zeros we get 45000
$44555 \simeq 45000$

(iii) To round off 86,943 to ten thousand
The digit in ten thousand places is 8
The digit to the right is $6>5$
Adding 1 to $8 \Rightarrow 8+1=9$.
Changing the digits to the right of 9 to zeroes we get 90,000
$86943 \simeq 90,000$

(iv) To round off 5081739 to lakhs
The digit in the lakhs place is 0
The digit to the right is $8>5$
Adding 1 to $0 \Rightarrow 1+0=1$
Changing the digits right off 51 to zeros
We get $51,00,000$
$5081739 \simeq 51,00,000$
(v) To round off 337598482 to ten crore
The digit in the ten crores place is 3
The digit to the right is $3<0$
The digit in ten crore place remains the same 3 .
Changing the digit to the right of 3 zeros we get $30,00,00,000$
$33,75,98,482 \simeq 30,00,00,000$

Question $4 .$
Estimate the sum of 157826 and 32469 rounded off to the nearest ten thousand. Solution:
$\begin{array}{rlr}
157,826 & \Rightarrow & 1,60,000 \\
\frac{32,469}{1,90,295} & \Rightarrow & \frac{30,000}{1,90,000} \\
\hline
\end{array}$

Question $5 .$
Estimate by rounding off each number to the nearest hundred.
(i) $8074+4178$
(ii) $1768977+130589$
Solution:
(i) $8074+4178$
$8074 \Rightarrow 8100$ $4178 \Rightarrow \frac{4200}{12,300}$ $1768977+130589$
(ii)
$\begin{aligned}
17,68,977 & \Rightarrow 1769000 \\
1,30,589 & \Rightarrow \frac{130600}{18,99,600} \\
\hline
\end{aligned}$

Question $6 .$
The population of a city was $43,43,645$ in the year 2001 and $46,81,087$ in the year 2011 . Estimate the increase in population by rounding off to the nearest thousand.
Solution:
Population in $2001=43,43,645$
Population in $2011=46,81,087$
Increase in population $=46,81,087-43,43,645=3,37,442$
When rounded off to the nearest thousand $=3,37,000$
 

Objective Type Questions

Question $7 .$
The number which on rounding off to nearest thousands given 11000 is
(a) 10345
(b) 10855
(c) 11799
(d) 10056
Solution:
(b) 10855
In 10855 , the digit in a hundred places is $8 \geq 5$. So 11000
 

Question 8 .
The estimation to the nearest hundred of 76812 is
(a) 77000
(b) 76000
(c) 76800
(d) 76900
Solution:
(c) 76800
 

Question $9 .$
The number 9785764 is rounded off to nearest lakh as
(a) 9800000
(b) 9786000
(c) 9795600
(d) 9795000
Solution:
(a) 9800000
In ten thousand places, the digit is 85 . So 9800000
 

Question $10 .$
The estimated difference of 167826 and 2765 rounded off to the nearest thousand is
(a) 180000
(b) 165000
(c) 140000
(d) 155000

Solution:

(b) 165000