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On March 11, 2024, 11:35 AM

Exercise 9.6 - Chapter 9 Differential Equations class 12 ncert solutions Maths - SaraNextGen [2024]


Question 1:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7893/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_1b1aafbb.gif

Answer:

The given differential equation is https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7893/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m17d07eed.gif

This is in the form of https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7893/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m9eca36b.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7893/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_3e6601f7.gif

The solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7893/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2683a848.gif

Therefore, equation (1) becomes:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7893/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_5dbcc9d0.gif

This is the required general solution of the given differential equation.

Question 2:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7895/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_4265ae04.gif

Answer:

The given differential equation is https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7895/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_4abad571.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7895/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m44fb59d3.gif

The solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7895/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m5ef00e3c.gif

This is the required general solution of the given differential equation.

Question 3:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7896/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m47878295.gif

Answer:

The given differential equation is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7896/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_ma890138.gif

The solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7896/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_6ed554fc.gif

This is the required general solution of the given differential equation.

Question 4:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7898/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m52de3e64.gif

Answer:

The given differential equation is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7898/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_38ace40c.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7898/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m685151a6.gif

Question 5:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7900/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_729f1347.gif

Answer:

The given differential equation is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7900/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6f57b166.gif

This equation is in the form of:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7900/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6515e221.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7900/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1904b50d.gif

Therefore, equation (1) becomes:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7900/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_26f0f191.gif

Question 6:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7901/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_71db7a18.gif

Answer:

The given differential equation is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7901/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2ca4951a.gif

This equation is in the form of a linear differential equation as:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7901/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_73dc8f1b.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7901/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_35c8c23a.gif

Question 7:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7903/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_65ce25e4.gif

Answer:

The given differential equation is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7903/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m3e0a10ab.gif

This equation is the form of a linear differential equation as:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7903/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_5bee6157.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7903/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m181d5d8f.gif

Substituting the value of https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7903/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_7d655c41.gif in equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7903/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m308278c3.gif

This is the required general solution of the given differential equation.

Question 8:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7905/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_443ac262.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7905/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_1a210f8c.gif

This equation is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7905/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_25e834d3.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7905/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6f7ba399.gif

Question 9:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7906/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_35bcedb.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7906/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_6d3eeb15.gif

This equation is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7906/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m70edc8c5.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7906/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m3352f4dc.gif

Question 10:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7908/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m233b1e32.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7908/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1c8b548d.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7908/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_2e3e1d0b.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7908/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_7f5de32a.gif

Question 11:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7910/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m30d6ca07.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7910/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6be0275d.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7910/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_4dcb382c.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7910/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m4a5295c4.gif

Question 12:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7912/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7b83ffae.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7912/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m36b3e21e.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7912/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2e76dd4a.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7912/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_mceaefd9.gif

Question 13:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7913/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m46699caa.gif

Answer:

The given differential equation is https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7913/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_7c135ba5.gif

This is a linear equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7913/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_164b1bc.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7913/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_9ac77ef.gif

Now,https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7913/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_7a54a15f.gif

Therefore,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7913/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7723e141.gif

Substituting C = –2 in equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7913/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m3fdc855b.gif

Hence, the required solution of the given differential equation is https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7913/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_4c1943cf.gif

Question 14:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7915/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m79313c45.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7915/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2493476.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7915/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m78eb719b.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7915/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m667cdaf1.gif

Now, y = 0 at x = 1.

Therefore,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7915/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2e59da6f.gif

Substituting https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7915/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m5a42a18d.gif  in equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7915/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1677fb1d.gif

This is the required general solution of the given differential equation.

Question 15:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7916/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_2bc24875.gif

Answer:

The given differential equation is https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7916/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_2a2e3262.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7916/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_e5c3fde.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7916/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2f02687b.gif

Now,https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7916/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1f7d64b.gif

Therefore, we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7916/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6af92dd4.gif

Substituting C = 4 in equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7916/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_701778ce.gif

This is the required particular solution of the given differential equation.

Question 16:

Find the equation of a curve passing through the origin given that the slope of the tangent to the curve at any point (xy) is equal to the sum of the coordinates of the point.

Answer:

Let F (xy) be the curve passing through the origin.

At point (xy), the slope of the curve will behttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7917/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_40c9fb2b.gif

According to the given information:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7917/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_1adff51a.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7917/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m611c1159.gif

The general solution of the given differential equation is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7917/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_3d135f28.gif

Substituting in equation (1), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7917/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2f3ce260.gif

The curve passes through the origin.

Therefore, equation (2) becomes:

1 = C

⇒ C = 1

Substituting C = 1 in equation (2), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7917/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_5499bef8.gif

Hence, the required equation of curve passing through the origin ishttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7917/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_37277475.gif

Question 17:

Find the equation of a curve passing through the point (0, 2) given that the sum of the coordinates of any point on the curve exceeds the magnitude of the slope of the tangent to the curve at that point by 5.

Answer:

Let F (xy) be the curve and let (xy) be a point on the curve. The slope of the tangent to the curve at (xy) is https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7919/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_40c9fb2b.gif

According to the given information:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7919/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m78fe3ce7.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7919/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_6cefc47.gif

The general equation of the curve is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7919/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6862464b.gif

Therefore, equation (1) becomes:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7919/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_1245dd5e.gif

The curve passes through point (0, 2).

Therefore, equation (2) becomes:

0 + 2 – 4 = Ce0

⇒ – 2 = C

⇒ C = – 2

Substituting C = –2 in equation (2), we get:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7919/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_1eaf5923.gif

This is the required equation of the curve.

Question 18:

The integrating factor of the differential equationhttps://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7920/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m1d5b7cce.gif  is

A. ex

B. ey

C. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7920/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_5fc97589.gif

D. x

Answer:

The given differential equation is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7920/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_3b3de514.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7920/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_5f80b8ce.gif

The integrating factor (I.F) is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7920/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m25b4e445.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7920/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_3cabfff6.gif

Hence, the correct Answer is C.

Question 19:

The integrating factor of the differential equation.

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_40b7eb5d.gif  is

A. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_4d8c2afd.gif

B. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m69b58c7f.gif

C. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_51fa168e.gif

D. https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m2cf58fa7.gif

Answer:

The given differential equation is:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m6d37cde9.gif

This is a linear differential equation of the form:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m7213cc48.gif

The integrating factor (I.F) is given by the relation,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m25b4e445.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/238/7921/NCERT_12-11-08_Gopal_12_Maths_Ex-9.1_12_MNK_SG_html_m469ddd2.gif

Hence, the correct Answer is D.

Also Read : Miscellaneous-Exercise-Chapter-9-Differential-Equations-class-12-ncert-solutions-Maths

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