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Exercise 3.1 - Chapter 3 Trigonometric Functions class 11 ncert solutions Maths - SaraNextGen [2024]


Question 1:

Find the radian measures corresponding to the following degree measures:

(i) 25° (ii) – 47° 30′ (iii) 240° (iv) 520°

Answer:

(i) 25°

We know that 180° = π radian

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5497/Chapter%203_html_m5511fce1.gif

(ii) –47° 30′

–47° 30′ =https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5497/Chapter%203_html_282d3c13.gif degree [1° = 60′]

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5497/Chapter%203_html_m326b3755.gif degree

Since 180° = π radian

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5497/Chapter%203_html_m8dac504.gif

(iii) 240°

We know that 180° = π radian

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5497/Chapter%203_html_m702dfd28.gif

(iv) 520°

We know that 180° = π radian

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5497/Chapter%203_html_73b103bf.gif

Question 2:

Find the degree measures corresponding to the following radian measures

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_meb7a1f7.gif.

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_m24c81b9e.gif (ii) – 4 (iii) https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_m179f0a59.gif (iv) https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_31b827a5.gif

Answer:

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_m24c81b9e.gif

We know that π radian = 180°

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_m8135e45.gif

(ii) – 4

We know that π radian = 180°

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_m59c35c04.gif

(iii) https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_m179f0a59.gif

We know that π radian = 180°

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_c74946e.gif

(iv) https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_31b827a5.gif

We know that π radian = 180°

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5498/Chapter%203_html_64198d2b.gif

Question 3:

A wheel makes 360 revolutions in one minute. Through how many radians does it turn in one second?

Answer:

Number of revolutions made by the wheel in 1 minute = 360

∴Number of revolutions made by the wheel in 1 second =https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5005/CHAPTER%203_html_m1c11c552.gif

In one complete revolution, the wheel turns an angle of 2π radian.

Hence, in 6 complete revolutions, it will turn an angle of 6 × 2π radian, i.e.,

12 π radian

Thus, in one second, the wheel turns an angle of 12π radian.

Question 4:

Find the degree measure of the angle subtended at the centre of a circle of radius 100 cm by an arc of length 22 cmhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5499/Chapter%203_html_m7f030a7b.gif.

Answer:

We know that in a circle of radius r unit, if an arc of length l unit subtends an angle θ radian at the centre, then

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5499/Chapter%203_html_m399eb0ee.gif

Therefore, forr = 100 cm, l = 22 cm, we have

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5499/Chapter%203_html_m6f6a7a70.gif

Thus, the required angle is 12°36′.

Question 5:

In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.

Answer:

Diameter of the circle = 40 cm

∴Radius (r) of the circle =https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5007/CHAPTER%203_html_7ce61241.gif

Let AB be a chord (length = 20 cm) of the circle.

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5007/CHAPTER%203_html_m12ebff2b.jpg

In ΔOAB, OA = OB = Radius of circle = 20 cm

Also, AB = 20 cm

Thus, ΔOAB is an equilateral triangle.

∴θ = 60° =https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5007/CHAPTER%203_html_40f07a87.gif

We know that in a circle of radius r unit, if an arc of length l unit subtends an angle θ radian at the centre, thenhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5007/CHAPTER%203_html_m69189415.gif.

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5007/CHAPTER%203_html_3bdee639.gif

Thus, the length of the minor arc of the chord ishttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5007/CHAPTER%203_html_m7139dae3.gif.

Question 6:

If in two circles, arcs of the same length subtend angles 60° and 75° at the centre, find the ratio of their radii.

Answer:

Let the radii of the two circles behttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5008/CHAPTER%203_html_755a413b.gif andhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5008/CHAPTER%203_html_m4a1afc13.gif. Let an arc of length l subtend an angle of 60° at the centre of the circle of radius r1, while let an arc of length subtend an angle of 75° at the centre of the circle of radius r2.

Now, 60° =https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5008/CHAPTER%203_html_40f07a87.gifand 75° =https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5008/CHAPTER%203_html_m3b7eabf0.gif

We know that in a circle of radius r unit, if an arc of length l unit subtends an angle θ radian at the centre, thenhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5008/CHAPTER%203_html_31575379.gif.

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5008/CHAPTER%203_html_m38ca7cc6.gif

Thus, the ratio of the radii is 5:4.

Question 7:

Find the angle in radian though which a pendulum swings if its length is 75 cm and the tip describes an arc of length

(i) 10 cm (ii) 15 cm (iii) 21 cm

Answer:

We know that in a circle of radius r unit, if an arc of length l unit subtends an angle θ radian at the centre, thenhttps://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5009/CHAPTER%203_html_m69189415.gif.

It is given that r = 75 cm

(i) Here, l = 10 cm

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5009/CHAPTER%203_html_m6810e2f2.gif

(ii) Here, = 15 cm

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5009/CHAPTER%203_html_m30dc3f.gif

(iii) Here, = 21 cm

https://img-nm.mnimgs.com/img/study_content/curr/1/11/11/163/5009/CHAPTER%203_html_191556dc.gif

Also Read : Exercise-3.2-Chapter-3-Trigonometric-Functions-class-11-ncert-solutions-Maths

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