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Exercise 2.2 (Revised) - Chapter 2 Polynomials class 10 ncert solutions Maths - SaraNextGen [2024-2025]


Exercise 2.2 (Revised) - Chapter 2 - Polynomials - Ncert Solutions class 10 Maths

Question 1:

Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_6637271c.gif https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_15577424.gif  https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_1960f190.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_6a227e02.gif https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m4e8b8e69.gif  https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m544e1c9.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_7592dfce.gif

The value of https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_2f20ebe3.gif is zero when x − 4 = 0 or + 2 = 0, i.e., when x = 4 or x = −2

Therefore, the zeroes of https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_2f20ebe3.gif are 4 and −2.

Sum of zeroes = https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_407b135.gif

Product of zeroes https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m1d59fef0.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_55df548c.gif

The value of 4s2 − 4s + 1 is zero when 2s − 1 = 0, i.e.,https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m76964103.gif

Therefore, the zeroes of 4s2 − 4s + 1 arehttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m5a4d85ce.gif andhttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m5a4d85ce.gif .

Sum of zeroes = https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_72609f8e.gif

Product of zeroes https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m1d8ce9f5.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m79cf68a8.gif

The value of 6x2 − 3 − 7x is zero when 3x + 1 = 0 or 2− 3 = 0, i.e., https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m55735b0c.gif orhttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m6f1b144a.gif

Therefore, the zeroes of 6x2 − 3 − 7x arehttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_ee4f088.gif .

Sum of zeroes = https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_15d94173.gif

Product of zeroes = https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_11f40d6e.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_46328b03.gif

The value of 4u2 + 8u is zero when 4u = 0 or u + 2 = 0, i.e., u = 0 or u = −2

Therefore, the zeroes of 4u2 + 8u are 0 and −2.

Sum of zeroes = https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_5b77cdc3.gif

Product of zeroes = https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_ce2134a.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m2f87022b.gif

The value of t2 − 15 is zero when https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m5381fefc.gif  or https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m5fe19534.gif , i.e., when https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_159f885f.gif

Therefore, the zeroes of t2 − 15 are https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m3dbe16dc.gif  andhttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_3a6ee18f.gif .

Sum of zeroes =https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m1ef338cd.gif

Product of zeroes = https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_274b9679.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_4eeb8c3a.gif

The value of 3x2 − x − 4 is zero when 3x − 4 = 0 or x + 1 = 0, i.e., when https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_m58bdc0f8.gif  or x = −1

Therefore, the zeroes of 3x2 − x − 4 are https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_37cb7ba8.gif and −1.

Sum of zeroes = https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_1861ce19.gif

Product of zeroes https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1917/Chapter%202_html_5393da64.gif

 

 

Question 2:

Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_356d3b80.gif  https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m4d8d6451.gif  https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_727f916a.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_7966df39.gif  https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_5e9652b.gif  https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m34bccdf5.gif

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_356d3b80.gif

Let the polynomial be https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m42d838f5.gif , and its zeroes behttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_4929f8da.gif  and https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_1de0ccf7.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_604e6400.gif

Therefore, the quadratic polynomial is 4x2 − x − 4.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m4d8d6451.gif

Let the polynomial be https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m42d838f5.gif , and its zeroes behttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_4929f8da.gif  and https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_1de0ccf7.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_63c7d134.gif

Therefore, the quadratic polynomial is 3x2 − https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_ma6b3e88.gif x + 1.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_727f916a.gif

Let the polynomial be https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m42d838f5.gif , and its zeroes behttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_4929f8da.gif  and https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_1de0ccf7.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_747ab6a6.gif

Therefore, the quadratic polynomial is https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_6440a2fb.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_12464645.gif

Let the polynomial be https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m42d838f5.gif , and its zeroes behttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_4929f8da.gif  and https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_1de0ccf7.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_39ddd646.gif

Therefore, the quadratic polynomial is https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m573cda3f.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_5e9652b.gif

Let the polynomial be https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m42d838f5.gif , and its zeroes behttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_4929f8da.gif  and https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_1de0ccf7.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m1d41b7e9.gif

Therefore, the quadratic polynomial is https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m66e68113.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_4ff9b915.gif

Let the polynomial be https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m42d838f5.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_43a033db.gif

Therefore, the quadratic polynomial ishttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/129/1920/Chapter%202_html_m15429d5.gif .

Also Read : Exercise-2.1-(Revised)-Chapter-2-Polynomials-class-10-ncert-solutions-Maths

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