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Exercise 3.3 (Revised) - Chapter 3 Pair Of Linear Equations In Two Variables class 10 ncert solutions Maths - SaraNextGen [2024-2025]


Exercise 3.3 (Revised) : Chapter 3 - Pair Of Linear Equations In Two Variables - Ncert Solutions class 10 - Maths

Question 1:

Solve the following pair of linear equations by the elimination method and the substitution method:

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_57459b1b.gif  https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m1b8ec1cd.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_7c81ac17.gif https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_d6d033.gif

Answer:

(i) By elimination method

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m6d4675d5.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_34bbbb8e.gif

Multiplying equation (1) by 2, we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m3c3469a.gif

Subtracting equation (2) from equation (3), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_1b785055.gif

Substituting the value in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m1f26fec3.gif

By substitution method

From equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_609aca22.gif  (5)

Putting this value in equation (2), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_7dd9b9ac.gif

−5y = −6

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_47fef0.gif

Substituting the value in equation (5), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m1f26fec3.gif

(ii) By elimination method

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m242f2f1b.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_2329091e.gif

Multiplying equation (2) by 2, we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m455d7ef3.gif

Adding equation (1) and (3), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_617a8d0b.gif

Substituting in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_43b1a7f.gif

Hence, x = 2, y = 1

By substitution method

From equation (2), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_56ed72a5.gif  (5)

Putting this value in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m6f7d100a.gif

7y = 7

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_14eb6a5b.gif

Substituting the value in equation (5), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_53722d3e.gif

(iii) By elimination method

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m6fe592aa.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_1a62b606.gif

Multiplying equation (1) by 3, we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m481873a4.gif

Subtracting equation (3) from equation (2), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_2c8e8811.gif

Substituting in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_2915ff5e.gif

∴ https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_69545581.gif

By substitution method

From equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_4c1154da.gif (5)

Putting this value in equation (2), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_675beb7.gif

Substituting the value in equation (5), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_726f4f5b.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m43d04808.gif

∴ https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_69545581.gif

(iv)By elimination method

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_7f7c4d46.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_1d256f4.gif

Subtracting equation (2) from equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m22d76b22.gif

Substituting this value in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_5b99b05b.gif

Hence, x = 2, y = −3

By substitution method

From equation (2), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_7d7d15b2.gif (5)

Putting this value in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m5e325de4.gif

5y = −15

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_m19dad446.gif

Substituting the value in equation (5), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2128/Chapter%203_html_60a85144.gif

∴ x = 2, y = −3

 

Question 2:

Form the pair of linear equations in the following problems, and find their solutions (if they exist) by the elimination method:

(i) If we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_m5a4d85ce.gif if we only add 1 to the denominator. What is the fraction?

(ii) Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu?

(iii) The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.

(iv) Meena went to bank to withdraw Rs 2000. She asked the cashier to give her Rs 50 and Rs 100 notes only. Meena got 25 notes in all. Find how many notes of Rs 50 and Rs 100 she received.

(v) A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Saritha paid Rs 27 for a book kept for seven days, while Susy paid Rs 21 for the book she kept for five days. Find the fixed charge and the charge for each extra day.

Answer:

(i)Let the fraction be https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_1141e1f1.gif .

According to the given information,

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_546898ad.gif

Subtracting equation (1) from equation (2), we obtain

= 3 (3)

Substituting this value in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_m764fbb8d.gif

Hence, the fraction is https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_648a2b75.gif .

(ii)Let present age of Nuri = x

and present age of Sonu = y

According to the given information,

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_393f7217.gif

Subtracting equation (1) from equation (2), we obtain

y = 20 (3)

Substituting it in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_d129155.gif

Hence, age of Nuri = 50 years

And, age of Sonu = 20 years

(iii)Let the unit digit and tens digits of the number be and y respectively. Then, number = 10y + x

Number after reversing the digits = 10x + y

According to the given information,

x + = 9 (1)

9(10y + x) = 2(10x + y)

88y − 11= 0

− x + 8=0 (2)

Adding equation (1) and (2), we obtain

9y = 9

y = 1 (3)

Substituting the value in equation (1), we obtain

x = 8

Hence, the number is 10y + x = 10 × 1 + 8 = 18

(iv)Let the number of Rs 50 notes and Rs 100 notes be x and respectively.

According to the given information,

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_69d88260.gif

Multiplying equation (1) by 50, we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_318781ff.gif

Subtracting equation (3) from equation (2), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_ma2a20f9.gif

Substituting in equation (1), we have x = 10

Hence, Meena has 10 notes of Rs 50 and 15 notes of Rs 100.

(v)Let the fixed charge for first three days and each day charge thereafter be Rs and Rs respectively.

According to the given information,

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_m428c73ae.gif

Subtracting equation (2) from equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_m60d45910.gif

Substituting in equation (1), we obtain

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/130/2134/Chapter%203_html_145d1415.gif

Hence, fixed charge = Rs 15

And Charge per day = Rs 3

Also Read : Exercise-3.2-(Revised)-Chapter-3-Pair-Of-Linear-Equations-In-Two-Variables-class-10-ncert-solutions-Maths

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