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Exercise 7.1 (Revised) - Chapter 7 Coordinate Geometry class 10 ncert solutions Maths - SaraNextGen [2024]


Exercise 7.1 (Revised) : Chapter 7 - Coordinate Geometry - Ncert Solutions class 10 - Maths

Question 1:

Find the distance between the following pairs of points:

(i) (2, 3), (4, 1) (ii) (−5, 7), (−1, 3) (iii) (ab), (− a, − b)

Answer:

(i) Distance between the two points is given by

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2951/Chapter%207_html_7d7d93be.gif

(ii) Distance between https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2951/Chapter%207_html_m78471312.gif is given by

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2951/Chapter%207_html_m357dbe00.gif

(iii) Distance between https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2951/Chapter%207_html_m40d26b98.gif is given by

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2951/Chapter%207_html_m7865a1a.gif

 

Question 2:

Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B discussed in Section 7.2.

Answer:

Distance between points https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2955/Chapter%207_html_m5a9fea8f.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2955/Chapter%207_html_624588d2.gif

Yes, we can find the distance between the given towns A and B.

Assume town A at origin point (0, 0).

Therefore, town B will be at point (36, 15) with respect to town A.

And hence, as calculated above, the distance between town A and B will be

39 km.

 

Question 3:

Determine if the points (1, 5), (2, 3) and (− 2, − 11) are collinear.

Answer:

Let the points (1, 5), (2, 3), and (−2, −11) be representing the vertices A, B, and C of the given triangle respectively.

Let https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2959/Chapter%207_html_6bd97df9.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2959/Chapter%207_html_1e338650.gif

Therefore, the points (1, 5), (2, 3), and (−2, −11) are not collinear.

 

Question 4:

Check whether (5, − 2), (6, 4) and (7, − 2) are the vertices of an isosceles triangle.

Answer:

Let the points (5, −2), (6, 4), and (7, −2) are representing the vertices A, B, and C of the given triangle respectively.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2964/Chapter%207_html_m1a9327b9.gif

As two sides are equal in length, therefore, ABCis an isosceles triangle.

 

Question 5:

In a classroom, 4 friends are seated at the points A, B, C and D as shown in the following figure. Champa and Chameli walk into the class and after observing for a few minutes Champa asks Chameli, “Don’t you think ABCD is a square?” Chameli disagrees.

Using distance formula, find which of them is correct.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2968/Chapter%207_html_dab30a8.jpg

Answer:

It can be observed that A (3, 4), B (6, 7), C (9, 4), and D (6, 1) are the positions of these 4 friends.

https://img-nm.mnimgs.com/img/study_content/content_ck_images/images/Selection_006(11).png

 CD=9-62+4-12=32+32=9+9=18=32https://img-nm.mnimgs.com/img/study_content/content_ck_images/images/Selection_008(21).png

 https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2968/Chapter%207_html_7fb595ec.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2968/Chapter%207_html_m388d7f38.jpg

It can be observed that all sides of this quadrilateral ABCD are of the same length and also the diagonals are of the same length.

Therefore, ABCD is a square and hence, Champa was correct

 

Question 6:

Name the type of quadrilateral formed, if any, by the following points, and give reasons for your Answer:

(i) (− 1, − 2), (1, 0), (− 1, 2), (− 3, 0)

(ii) (− 3, 5), (3, 1), (0, 3), (− 1, − 4)

(iii) (4, 5), (7, 6), (4, 3), (1, 2)

Answer:

(i) Let the points (−1, −2), (1, 0), (−1, 2), and (−3, 0) be representing the vertices A, B, C, and D of the given quadrilateral respectively.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2979/Chapter%207_html_4ce92c36.gif

It can be observed that all sides of this quadrilateral are of the same length and also, the diagonals are of the same length. Therefore, the given points are the vertices of a square.

(ii)Let the points (− 3, 5), (3, 1), (0, 3), and (−1, −4) be representing the vertices A, B, C, and D of the given quadrilateral respectively.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2979/Chapter%207_html_364cc549.gif

It can be observed that all sides of this quadrilateral are of different lengths. Therefore, it can be said that it is only a general quadrilateral, and not specific such as square, rectangle, etc.

(iii)Let the points (4, 5), (7, 6), (4, 3), and (1, 2) be representing the vertices A, B, C, and D of the given quadrilateral respectively.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2979/Chapter%207_html_71247f73.gif

It can be observed that opposite sides of this quadrilateral are of the same length. However, the diagonals are of different lengths. Therefore, the given points are the vertices of a parallelogram.

Question 7:

Find the point on the x-axis which is equidistant from (2, − 5) and (− 2, 9).

Answer:

We have to find a point on x-axis. Therefore, its y-coordinate will be 0.

Let the point on x-axis behttps://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2981/Chapter%207_html_2379183f.gif .

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2981/Chapter%207_html_m39c218.gif

By the given condition, these distances are equal in measure.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2981/Chapter%207_html_16ddf86e.gif

Therefore, the point is (− 7, 0).

 

Question 8:

Find the values of y for which the distance between the points P (2, − 3) and Q (10, y) is 10 units.

Answer:

It is given that the distance between (2, −3) and (10, y) is 10.

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2984/Chapter%207_html_m322313ab.gif

 

Question 9:

If Q (0, 1) is equidistant from P (5, − 3) and R (x, 6), find the values of x. Also find the distance QR and PR.

Answer:

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2989/Chapter%207_html_4fd96130.gif

Therefore, point R is (4, 6) or (−4, 6).

When point R is (4, 6),

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2989/Chapter%207_html_7d9e60a8.gif

When point R is (−4, 6),

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2989/Chapter%207_html_1d09435e.gif

 

Question 10:

Find a relation between x and y such that the point (xy) is equidistant from the point (3, 6) and (− 3, 4).

Answer:

Point (xy) is equidistant from (3, 6) and (−3, 4).

https://img-nm.mnimgs.com/img/study_content/curr/1/10/9/134/2993/Chapter%207_html_4d631a98.gif

Also Read : Exercise-7.2 (Revised)-Chapter-7-Coordinate-Geometry-class-10-ncert-solutions-Maths

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