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On April 21, 2024, 11:35 AM

Exercise 4.4 - Chapter 4 Practical Geometry class 8 ncert solutions Maths - SaraNextGen [2024-2025]


Question 1:

Construct the following quadrilaterals,

(i) Quadrilateral DEAR

DE = 4 cm

EA = 5 cm

AR = 4.5 cm

∠E = 60°

∠A = 90°

(ii) Quadrilateral TRUE

TR = 3.5 cm

RU = 3 cm

UE = 4 cm

∠R = 75°

∠U = 120°

Answer:

(i)

(1)A rough sketch of this quadrilateral can be drawn as follows.

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/67/3279/Chapter%204_html_29d866aa.jpg

(2) Draw a line segment DE of 4 cm and an angle of 60º at point E. As vertex A is 5 cm away from vertex E, cut a line segment EA of 5 cm from this ray.

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/67/3279/Chapter%204_html_23ca8ba7.jpg

(3) Again draw an angle of 90º at point A. As vertex R is 4.5 cm away from vertex A, cut a line segment RA of 4.5 cm from this ray.

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/67/3279/Chapter%204_html_13bdad29.jpg

(4) Join D to R.

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/67/3279/Chapter%204_html_616cd179.jpg

DEAR is the required quadrilateral.

(ii)

(1)A rough sketch of this quadrilateral can be drawn as follows.

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/67/3279/Chapter%204_html_mc29f4c9.jpg

(2) Draw a line segment RU of 3 cm and an angle of 120º at point U. As vertex E is 4 cm away from vertex U, cut a line segment UE of 4 cm from this ray.

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/67/3279/Chapter%204_html_m46b9f6.jpg

(3) Next, draw an angle of 75º at point R. As vertex T is 3.5 cm away from vertex R, cut a line segment RT of 3.5 cm from this ray.

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/67/3279/Chapter%204_html_447ff89.jpg

(4) Join T to E.

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/67/3279/Chapter%204_html_m40f5051d.jpg

TRUE is the required quadrilateral.

Also Read : Exercise-4.5-Chapter-4-Practical-Geometry-class-8-ncert-solutions-Maths

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