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Exercise 12.1 - Chapter 12 Exponents & Powers class 8 ncert solutions Maths - SaraNextGen [2024-2025]


Updated By SaraNextGen
On April 24, 2024, 11:35 AM

Question 1:

Evaluate

(i) 3−2 (ii) (−4)−2 (iii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2604/Chapter%2012_html_75b62cde.gif

Answer:

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2604/Chapter%2012_html_m12989fa3.gif

(ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2604/Chapter%2012_html_291f555.gif

(iii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2604/Chapter%2012_html_539b029.gif

Question 2:

Simplify and express the result in power notation with positive exponent.

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_3045066d.gif  (ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_7c68a770.gif

(iii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_m4d3ed5f8.gif  (iv) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_m15df1ca3.gif

(v) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_47ad53e0.gif

Answer:

(i) (−4)5 ÷ (−4)8 = (−4)5 − 8 (am ÷ an = am − n)

= (− 4)−3

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_65eee8db.gif

(ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_4d6c53.gif

(iii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_m825c5d9.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_6465b8b2.gif

(iv) (3− 7 ÷ 3−10) × 3−5 = (3−7 − (−10)) × 3−5 (am ÷ an = a− n)

= 33 × 3−5

= 33 + (− 5) (am × an = am + n)

= 3−2

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_m18be1396.gif

(v) 2−3 × (−7)−3 = https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_m6bc7bc4c.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2608/Chapter%2012_html_66d33d7b.gif

Question 3:

Find the value of.

(i) (30 + 4−1) × 22 (ii) (2−1 × 4−1) ÷2−2

(iii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_44570ee0.gif  (iv) (3−1 + 4−1 + 5−1)0

(v) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_3d0390df.gif

Answer:

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_m7669d754.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_64430adf.gif

(ii) (2−1 × 4−1) ÷ 2− 2 = [2−1 × {(2)2}− 1] ÷ 2− 2

= (2− 1 × 2− 2) ÷ 2− 2 https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_7d74e5df.gif

= 2−1+ (−2) ÷ 2−2 (am × an = am + n)

= 2−3 ÷ 2−2

= 2−3 − (−2) (am ÷ an = am − n)

= 2−3 + 2 = 2 −1

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_64dbc94b.gif

(iii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_1aabec55.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_40a0c725.gif

(iv) (3−1 + 4−1 + 5−1)0

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_m13ddf2e0.gif

= 1 (a0 = 1)

(v) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_14e770eb.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2614/Chapter%2012_html_6757125.gif

Question 4:

Evaluate (i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2617/Chapter%2012_html_3da8c67e.gif  (ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2617/Chapter%2012_html_761319f6.gif

Answer:

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2617/Chapter%2012_html_4124e11c.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2617/Chapter%2012_html_m12430df2.gif

(ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2617/Chapter%2012_html_20bca225.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2617/Chapter%2012_html_m1b40ed31.gif

Question 5:

Find the value of m for which 5m ÷5−3 = 55.

Answer:

5m ÷ 5−3 = 55

5m − (− 3) = 55 (am ÷ an = am − n)

5m + 3 = 55

Since the powers have same bases on both sides, their respective exponents must be equal.

m + 3 = 5

m = 5 − 3

m = 2

Question 6:

Evaluate (i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2623/Chapter%2012_html_47369670.gif  (ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2623/Chapter%2012_html_m49f56270.gif

Answer:

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2623/Chapter%2012_html_699c59cb.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2623/Chapter%2012_html_7db2f8c1.gif

(ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2623/Chapter%2012_html_mde0dfa3.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2623/Chapter%2012_html_m31a73b3b.gif

Question 7:

Simplify. (i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2625/Chapter%2012_html_m3f8c02b.gif  (ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2625/Chapter%2012_html_13784182.gif

Answer:

(i) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2625/Chapter%2012_html_m57fd0cc4.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2625/Chapter%2012_html_m446adf04.gif

(ii) https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2625/Chapter%2012_html_5301372f.gif

https://img-nm.mnimgs.com/img/study_content/curr/1/8/5/75/2625/Chapter%2012_html_m27c1e8fd.gif

Also Read : Exercise-12.2-Chapter-12-Exponents-&-Powers-class-8-ncert-solutions-Maths

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