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On January 25, 2024, 11:35 AM

Exercise 10.3 - Chapter 10 Practical Geometry class 7 ncert solutions Maths - SaraNextGen [2024]


Question 1:

Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

Answer:

The rough sketch of the required ΔDEF is as follows.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1464/Chapter%2010_html_2b5aee4d.jpg

The steps of construction are as follows.

(i)Draw a line segment DE of length 5 cm.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1464/Chapter%2010_html_m7b26fc28.jpg

(ii) At point D, draw a ray DX making an angle of 90° with DE.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1464/Chapter%2010_html_406a979a.jpg

(iii) Taking D as centre, draw an arc of 3 cm radius. It will intersect DX at point F.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1464/Chapter%2010_html_57ba7b59.jpg

(iv) Join F to E. ΔDEF is the required triangle.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1464/Chapter%2010_html_c0dcbb6.jpg

Question 2:

Construct an isosceles triangle in which the lengths of each of its equal sides

is 6.5 cm and the angle between them is 110°.

Answer:

An isosceles triangle PQR has to be constructed with PQ = QR = 6.5 cm. A rough sketch of the required triangle can be drawn as follows.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1466/Chapter%2010_html_m62a20bbd.jpg

The steps of construction are as follows.

(i) Draw the line segment QR of length 6.5 cm.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1466/Chapter%2010_html_m255b8aee.jpg

(ii) At point Q, draw a ray QX making an angle 110° with QR.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1466/Chapter%2010_html_4b4ff48a.jpg

(iii) Taking Q as centre, draw an arc of 6.5 cm radius. It intersects QX at point P.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1466/Chapter%2010_html_36d643cc.jpg

(iv) Join P to R to obtain the required triangle PQR.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1466/Chapter%2010_html_m4bb4a08.jpg

Question 3:

Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

Answer:

A rough sketch of the required triangle is as follows.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1468/Chapter%2010_html_m5beffff5.jpg

The steps of construction are as follows.

(i) Draw a line segment BC of length 7.5 cm.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1468/Chapter%2010_html_m3e835ef0.jpg

(ii) At point C, draw a ray CX making 60º with BC.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1468/Chapter%2010_html_m74c37036.jpg

(iii) Taking C as centre, draw an arc of 5 cm radius. It intersects CX at point A.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1468/Chapter%2010_html_799e62ea.jpg

(iv) Join A to B to obtain triangle ABC.

https://img-nm.mnimgs.com/img/study_content/curr/1/7/3/40/1468/Chapter%2010_html_m7526afa4.jpg

Also Read : Exercise-10.4-Chapter-10-Practical-Geometry-class-7-ncert-solutions-Maths

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