A rod of length
and mass
is kept on a horizontal smooth plane. It is free to rotate and move. A particle of same mass
moving on the plane with velocity
strikes the rod at point
making angle
with the rod. The collision is elastic. After collision,
a) |
The angular velocity of the rod will be 72/55 |
b) |
The center of the rod will travel a distance |
c) |
Impulse of the impact force is |
d) |
None of these |
A rod of length
and mass
is kept on a horizontal smooth plane. It is free to rotate and move. A particle of same mass
moving on the plane with velocity
strikes the rod at point
making angle
with the rod. The collision is elastic. After collision,
a) |
The angular velocity of the rod will be 72/55 |
b) |
The center of the rod will travel a distance |
c) |
Impulse of the impact force is |
d) |
None of these |
(a,b,c)
The ball has component of its velocity perpendicular to the length of the rod immediately after collision.
is the velocity of CM of the rod and
is angular velocity of the rod just after collision. The ball strikes the rod with a speed of
in the perpendicular direction and its component along the length of the after the collision is unchanged
Using for the point of collision
Velocity of separation= Velocity of approach
…(i)
Conserving linear momentum (of rod+ particle) in the direction perpendicular to the rod
…(ii)
Conserving angular momentum about point as shown in the figure
Time taken rotate by angle,
In the same time, distance travelled =
Using angular impulse- angular momentum equation
[Using impulse-momentum equation on the rod