Last Updated On [03-11-2023]
A uniform cylinder of mass 
rests on two rough horizontal planks. A thread is wound on the cylinder. The hanging end of the thread is pulled vertically down with a constant force 
a)
Since horizontal acceleration is provided by the friction acting on the cylinder, its translation kinetic energy 
is equal to work done by this friction
b)
Since moment about instantaneous axis of rotation is produced by force 
kinetic 
is equal to work done by 
where 
ismoment of inertia about the instantaneous axis of rotation and 
is the angular velocity
c)
Since cylinder is moving, energy is lost against friction
d)
Work done by 
+ work done by friction on cylinder =total KE of the cylinder
A uniform cylinder of mass rests on two rough horizontal planks. A thread is wound on the cylinder. The hanging end of the thread is pulled vertically down with a constant force
a)
Since horizontal acceleration is provided by the friction acting on the cylinder, its translation kinetic energy is equal to work done by this friction
b)
Since moment about instantaneous axis of rotation is produced by force kinetic is equal to work done by where ismoment of inertia about the instantaneous axis of rotation and is the angular velocity
c)
Since cylinder is moving, energy is lost against friction
d)
Work done by + work done by friction on cylinder =total KE of the cylinder
Question ID - 100837 :-
A uniform cylinder of mass rests on two rough horizontal planks. A thread is wound on the cylinder. The hanging end of the thread is pulled vertically down with a constant force
a)
Since horizontal acceleration is provided by the friction acting on the cylinder, its translation kinetic energy is equal to work done by this friction
b)
Since moment about instantaneous axis of rotation is produced by force kinetic is equal to work done by where ismoment of inertia about the instantaneous axis of rotation and is the angular velocity
c)
Since cylinder is moving, energy is lost against friction
d)
Work done by + work done by friction on cylinder =total KE of the cylinder
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A uniform cylinder of mass |
|
|
a) |
Since horizontal acceleration is provided by the friction acting on the cylinder, its translation kinetic energy |
|
b) |
Since moment about instantaneous axis of rotation is produced by force |
|
c) |
Since cylinder is moving, energy is lost against friction |
|
d) |
Work done by |
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(b,a) When force Since the work is done by If |
acts vertically downwards on the thread, the thread unwinds and the cylinder rotates clockwise. Hence, its surface tries to slip over the planks in a backward direction.Hence, a friction comes into existence and acts on the cylinder in a forward direction (rightward direction). It is the only horizontal force acting on the cylinder. Due to the friction, cylinder experiences a rightward translational acceleration.But the point at which the friction acts remains always at rest, therefore no energy is lost against the friction
and no energy is lost against the friction, therefore total kinetic energy of the cylinder at any instant is equal to work done by 
. Hence, options (a) and (c) are incorrect and option (d) is correct
is the moment of inertia of a body about its instantaneous axis of rotation, then the total KE of the rotating body is equal to 
. Hence, option (b) is correctNext Question :
There are four terms/figures in the question. The terms right to the symbol : : have same relationship as the two terms of the left symbol : : Out of the four terms/figure one is missing, which is shown by(?). Four alternatives are given for each question. Find out the correct alternative.
|
Durandcup : Football : : Ubercup : ? |
|||||||
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(a) |
Golf |
(b) |
Badminton |
(c) |
Hockey |
(d) |
Chess |
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