In each situation of column I, a system involving two bodies is given. All strings and pulleys are light and friction is absent everywhere. Initially, each body of every system is at rest. Consider the system in all situations of column I from rest till any collision occurs. Then match the statements in column I with the corresponding results in column II
Column-I
Column- II
(A)
The block plus wedge system is placed over smooth horizontal surface. After the system is released from rest, the centre of mass of system
.png)
(p)
Shifts towards right
(B)
The string connecting both the blocks of mass 
is horizontal. The left block is placed over smooth horizontal table as shown. After the two blocks system is released from rest, the centre of mass of system
.png)
(q)
Shifts downwards
(C)
The block and the monkey have the same mass. The monkey starts climbing up the rope. After the monkey starts climbing up, the centre of mass of monkey + block system
.png)
(r)
Shifts upwards
(D)
Both blocks of mass
are initially at rest. The left block is given initial at rest. The left block is given initial velocity 
downwards. Then, the centre of mass of two–block system afterwards
.png)
(s)
Does not shift
CODES :
A
B
C
D
a)
d
a
c
b
b)
c
d
b
a
c)
b
a
c
d
d)
b
c
d
a
In each situation of column I, a system involving two bodies is given. All strings and pulleys are light and friction is absent everywhere. Initially, each body of every system is at rest. Consider the system in all situations of column I from rest till any collision occurs. Then match the statements in column I with the corresponding results in column II
Column-I
Column- II
(A)
The block plus wedge system is placed over smooth horizontal surface. After the system is released from rest, the centre of mass of system
(p)
Shifts towards right
(B)
The string connecting both the blocks of mass is horizontal. The left block is placed over smooth horizontal table as shown. After the two blocks system is released from rest, the centre of mass of system
(q)
Shifts downwards
(C)
The block and the monkey have the same mass. The monkey starts climbing up the rope. After the monkey starts climbing up, the centre of mass of monkey + block system
(r)
Shifts upwards
(D)
Both blocks of mass are initially at rest. The left block is given initial at rest. The left block is given initial velocity downwards. Then, the centre of mass of two–block system afterwards
(s)
Does not shift
CODES :
A
B
C
D
a)
d
a
c
b
b)
c
d
b
a
c)
b
a
c
d
d)
b
c
d
a
Question ID - 101069 | SaraNextGen Top Answer
In each situation of column I, a system involving two bodies is given. All strings and pulleys are light and friction is absent everywhere. Initially, each body of every system is at rest. Consider the system in all situations of column I from rest till any collision occurs. Then match the statements in column I with the corresponding results in column II
Column-I
Column- II
(A)
The block plus wedge system is placed over smooth horizontal surface. After the system is released from rest, the centre of mass of system
(p)
Shifts towards right
(B)
The string connecting both the blocks of mass is horizontal. The left block is placed over smooth horizontal table as shown. After the two blocks system is released from rest, the centre of mass of system
(q)
Shifts downwards
(C)
The block and the monkey have the same mass. The monkey starts climbing up the rope. After the monkey starts climbing up, the centre of mass of monkey + block system
(r)
Shifts upwards
(D)
Both blocks of mass are initially at rest. The left block is given initial at rest. The left block is given initial velocity downwards. Then, the centre of mass of two–block system afterwards
(s)
Does not shift
CODES :
A
B
C
D
a)
d
a
c
b
b)
c
d
b
a
c)
b
a
c
d
d)
b
c
d
a
|
In each situation of column I, a system involving two bodies is given. All strings and pulleys are light and friction is absent everywhere. Initially, each body of every system is at rest. Consider the system in all situations of column I from rest till any collision occurs. Then match the statements in column I with the corresponding results in column II |
|
Column-I |
Column- II |
||
|
(A) |
The block plus wedge system is placed over smooth horizontal surface. After the system is released from rest, the centre of mass of system
|
(p) |
Shifts towards right |
|
(B) |
The string connecting both the blocks of mass
|
(q) |
Shifts downwards |
|
(C) |
The block and the monkey have the same mass. The monkey starts climbing up the rope. After the monkey starts climbing up, the centre of mass of monkey + block system
|
(r) |
Shifts upwards |
|
(D) |
Both blocks of mass
|
(s) |
Does not shift |
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CODES : |
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A |
B |
C |
D |
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a) |
d |
a |
c |
b |
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b) |
c |
d |
b |
a |
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c) |
b |
a |
c |
d |
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d) |
b |
c |
d |
a |
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(c) i. Initial velocity of centre of mass of given system is zero and net external force is in vertical direction. Since there is shift of mass downwards, the centre of mass has only downward shift ii. Obviously, there is shift of centre of mass of given system downwards. Also the pulley exerts a force on string which has a horizontal component towards right Hence, centre of mass of system has rightward shift iii. Both block and monkey move up, hence centre of mass of the given system shifts vertically upwards iv. Net external force on given system is zero. Hence, centre of mass of the given system remains at rest |