A uniform rod of mass 
kg and length 
is suspend by two smooth hinges 1 and 2 as shown in Fig. A force 
N is applied downward at a distance 
from hinge 2. Due to the application of force 
hinge 2 breaks. At this instant, applied force 
is also removed. The rod starts to ratate downward about hinge 1. 
)
.png)
The reaction at hinge 1, before hinge 2 breaks, is
a)
24N
b)
12N
c)
11N
d)
10N
kg and length is suspend by two smooth hinges 1 and 2 as shown in Fig. A force N is applied downward at a distance from hinge 2. Due to the application of force hinge 2 breaks. At this instant, applied force is also removed. The rod starts to ratate downward about hinge 1. )The reaction at hinge 1, before hinge 2 breaks, is
a)
24N
b)
12N
c)
11N
d)
10N
Question ID - 101276 | SaraNextGen Top Answer A uniform rod of mass kg and length is suspend by two smooth hinges 1 and 2 as shown in Fig. A force N is applied downward at a distance from hinge 2. Due to the application of force hinge 2 breaks. At this instant, applied force is also removed. The rod starts to ratate downward about hinge 1. )
The reaction at hinge 1, before hinge 2 breaks, is
a)
24N
b)
12N
c)
11N
d)
10N
A uniform rod of mass kg and length is suspend by two smooth hinges 1 and 2 as shown in Fig. A force N is applied downward at a distance from hinge 2. Due to the application of force hinge 2 breaks. At this instant, applied force is also removed. The rod starts to ratate downward about hinge 1. )
|
The reaction at hinge 1, before hinge 2 breaks, is |
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|
a) |
24N |
b) |
12N |
c) |
11N |
d) |
10N |
(c)
.png)
As the rod is in equilibrium,
Taking torque about hinge 2, we get
