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A stone of mass , tied to the end of a string, is whirled around in a horizontal circle (neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant.Then the tension in the string is given by  where  is a constant,  is the instantaneous radius of the circle and  is



Question ID - 101413 | SaraNextGen Top Answer

A stone of mass , tied to the end of a string, is whirled around in a horizontal circle (neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant.Then the tension in the string is given by  where  is a constant,  is the instantaneous radius of the circle and  is

1 Answer
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Answer Key / Explanation : (3) -

(3)

For circular motion of the stone,

[as g = 0]      (i)

and as A.M. is constant,

i.e., (ii)

Eliminating  between Eqs. (i) and (ii), we get

Or  with (iii)

Comparing Eqs.(iii) with , we find

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