A frog sits on the end of a long board of length 
The board rests on a frictionless horizontal table. The frog wants to jump to the opposite end of the board. What is the minimum take-off speed (in m/s), i.e., relative to ground ‘
’ that allows the frog to do the trick? The board and the frog have equal masses
The board rests on a frictionless horizontal table. The frog wants to jump to the opposite end of the board. What is the minimum take-off speed (in m/s), i.e., relative to ground ‘ ’ that allows the frog to do the trick? The board and the frog have equal massesQuestion ID - 101438 | SaraNextGen Top Answer A frog sits on the end of a long board of length The board rests on a frictionless horizontal table. The frog wants to jump to the opposite end of the board. What is the minimum take-off speed (in m/s), i.e., relative to ground ‘ ’ that allows the frog to do the trick? The board and the frog have equal masses
A frog sits on the end of a long board of length The board rests on a frictionless horizontal table. The frog wants to jump to the opposite end of the board. What is the minimum take-off speed (in m/s), i.e., relative to ground ‘ ’ that allows the frog to do the trick? The board and the frog have equal masses
1 Answer
127 votes
Answer Key / Explanation : (2) -
(2)
Apply conservation of momentum in horizontal direction:
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Solve to get
for minimum
, Hence 
2
127 votes
Answer Link
127