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The maximum number of possible interference maxima for slit-separation equal to twice the wavelength is Young’s double-slit experiment, is

a)

Infinite

b)

Five

c)

Three

d)

Zero


Question ID - 150050 | SaraNextGen Answer

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength is Young’s double-slit experiment, is

a)

Infinite

b)

Five

c)

Three

d)

Zero

1 Answer - 5876 Votes

3537

Answer Key : (b) -

(b)

For possible interference maxima on the screen, the condition is

                                           …(i)

Given :  slit-width

The maximum value of  is 1, hence,

Thus, Eq. (i) must be satisfied by 5 integer values ie, -2 -1, 0, 1, 2.  Hence, the maximum number of possible interference maxima is 5.



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