The maximum number of possible interference maxima for slit-separation equal to twice the wavelength is Young’s double-slit experiment, is |
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a) |
Infinite |
b) |
Five |
c) |
Three |
d) |
Zero |

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength is Young’s double-slit experiment, is |
|||||||

a) |
Infinite |
b) |
Five |
c) |
Three |
d) |
Zero |

1 Answer

127 votes

For possible interference maxima on the screen, the condition is …(i) Given : slit-width The maximum value of is 1, hence, Thus, Eq. (i) must be satisfied by 5 integer values ie, -2 -1, 0, 1, 2. Hence, the maximum number of possible interference maxima is 5. |

127 votes

127