Last Updated On 01-06-2023 - By Jeesha Sara
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is
a)
Infinite
b)
Five
c)
Three
d)
Zero
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is
a)
Infinite
b)
Five
c)
Three
d)
Zero
Question ID - 150147 :-
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is
a)
Infinite
b)
Five
c)
Three
d)
Zero
|
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is |
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|
a) |
Infinite |
b) |
Five |
c) |
Three |
d) |
Zero |
|
(b) For maxima
Since value of
Therefore only five maximas can be obtained on both side of the screen |
can not be greater 1
Next Question :
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The condition for obtaining secondary maxima in the diffraction pattern due to single slit is |
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a) |
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b) |
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c) |
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d) |
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