The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is
a)
Infinite
b)
Five
c)
Three
d)
Zero
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is
a)
Infinite
b)
Five
c)
Three
d)
Zero
Question ID - 150147 | SaraNextGen Answer
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is
a)
Infinite
b)
Five
c)
Three
d)
Zero
|
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is |
|||||||
|
a) |
Infinite |
b) |
Five |
c) |
Three |
d) |
Zero |
1 Answer - 5876 Votes
3537
Answer Key : (b) -
Answer Link|
(b) For maxima
Since value of
Therefore only five maximas can be obtained on both side of the screen |
can not be greater 1
