The circuit shown here is used to compare the emf of two cells 
and
.
The null point is at 
when the galvanometer is connected to 
. when the galvanometer is connected to 
, the null point will be
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|
a) |
To the left of |
b) |
To the right of |
c) |
At |
d) |
None where on |
Question ID - 150286 | SaraNextGen Answer The circuit shown here is used to compare the emf of two cells and .
The null point is at when the galvanometer is connected to . when the galvanometer is connected to , the null point will be
a)
To the left of 
b)
To the right of 
c)
At 
itself
d)
None where on 
The circuit shown here is used to compare the emf of two cells and .
The null point is at when the galvanometer is connected to . when the galvanometer is connected to , the null point will be
|
a) |
To the left of |
b) |
To the right of |
c) |
At |
d) |
None where on |
1 Answer - 5876 Votes
3537
Answer Key : (a) -
Answer Link|
(a)
|
. As, 
, therefore 
. Therefore the null point for thr cell of emf 
must be at shorter length than that of cell 
Thus null point on potentiometer wire should shift towards left of 
.