Last Updated On 01-06-2023 - By Jeesha Sara
The circuit shown here is used to compare the emf of two cells 
and
.
The null point is at 
when the galvanometer is connected to 
. when the galvanometer is connected to 
, the null point will be
.png)
|
a) |
To the left of |
b) |
To the right of |
c) |
At |
d) |
None where on |
Question ID - 150286 :- The circuit shown here is used to compare the emf of two cells and .
The null point is at when the galvanometer is connected to . when the galvanometer is connected to , the null point will be
a)
To the left of 
b)
To the right of 
c)
At 
itself
d)
None where on 
The circuit shown here is used to compare the emf of two cells and .
The null point is at when the galvanometer is connected to . when the galvanometer is connected to , the null point will be
|
a) |
To the left of |
b) |
To the right of |
c) |
At |
d) |
None where on |
|
(a)
|
. As, 
, therefore 
. Therefore the null point for thr cell of emf 
must be at shorter length than that of cell 
Thus null point on potentiometer wire should shift towards left of 
.Next Question :
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A cell of constant emf first connected to a resistance |
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|
a) |
|
b) |
|
c) |
|
d) |
|
and then connected to a resistance
.
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