The circuit shown here is used to compare the emf of two cells 
and
.
The null point is at 
when the galvanometer is connected to 
. when the galvanometer is connected to 
, the null point will be
.png)
a)
To the left of 
b)
To the right of 
c)
At 
itself
d)
None where on 
and . when the galvanometer is connected to . when the galvanometer is connected to , the null point will bea)
To the left of
b)
To the right of
c)
At itself
d)
None where on
Question ID - 150286 | SaraNextGen Top Answer The circuit shown here is used to compare the emf of two cells and .
The null point is at when the galvanometer is connected to . when the galvanometer is connected to , the null point will be
a)
To the left of
b)
To the right of
c)
At itself
d)
None where on
The circuit shown here is used to compare the emf of two cells and .
The null point is at when the galvanometer is connected to . when the galvanometer is connected to , the null point will be
|
a) |
To the left of |
b) |
To the right of |
c) |
At |
d) |
None where on |
1 Answer
127 votes
Answer Key / Explanation : (a) -
|
(a)
|
. As, 
, therefore 
. Therefore the null point for thr cell of emf 
must be at shorter length than that of cell 
Thus null point on potentiometer wire should shift towards left of 
.127 votes
Answer Link
127