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A light emitting diode (LED) has a voltage drop of 2 V across it and passes a current of 10 mA. When it operates with 6 V battery through a limiting resistor , the value of  is

a)

40 k

b)

4 k

c)

200

d)

400


Question ID - 150712 | Toppr Answer

A light emitting diode (LED) has a voltage drop of 2 V across it and passes a current of 10 mA. When it operates with 6 V battery through a limiting resistor , the value of  is

a)

40 k

b)

4 k

c)

200

d)

400

1 Answer - 5876 Votes

3537

Answer Key : (d) -

(d)

Current in the circuit = 10 mA =  A

and       voltage in the circuit = 6 4 V

from Ohm’s law,



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