A light emitting diode (LED) has a voltage drop of 2 V across it and passes a current of 10 mA. When it operates with 6 V battery through a limiting resistor 
, the value of 
is
a)
40 k
b)
4 k
c)
200 
d)
400 
A light emitting diode (LED) has a voltage drop of 2 V across it and passes a current of 10 mA. When it operates with 6 V battery through a limiting resistor , the value of is
a)
40 k
b)
4 k
c)
200
d)
400
Question ID - 150712 | SaraNextGen Top Answer
A light emitting diode (LED) has a voltage drop of 2 V across it and passes a current of 10 mA. When it operates with 6 V battery through a limiting resistor , the value of is
a)
40 k
b)
4 k
c)
200
d)
400
|
A light emitting diode (LED) has a voltage drop of 2 V across it and passes a current of 10 mA. When it operates with 6 V battery through a limiting resistor |
|||||||
|
a) |
40 k |
b) |
4 k |
c) |
200 |
d) |
400 |
1 Answer
127 votes
Answer Key / Explanation : (d) -
|
(d) Current in the circuit = 10 mA = and voltage in the circuit = 6 from Ohm’s law,
|
A
4 V
127 votes
Answer Link
127