The diode shown in the circuit is a silicon diode. The potential difference between the points 
and 
will be
.png)
a)
6 
b)
0.6 
c)
0.7 
d)
0 
and will bea)
6
b)
0.6
c)
0.7
d)
0
Question ID - 150759 | SaraNextGen Top Answer The diode shown in the circuit is a silicon diode. The potential difference between the points and will be
a)
6
b)
0.6
c)
0.7
d)
0
The diode shown in the circuit is a silicon diode. The potential difference between the points and will be
|
a) |
6 |
b) |
0.6 |
c) |
0.7 |
d) |
0 |
1 Answer
127 votes
Answer Key / Explanation : (a) -
|
(a) In the given condition diode is in reverse biasing so it acts as open circuit. Hence potential difference between |
and 
is 
127 votes
Answer Link
127