If the probability of a six-digit number  whose six digit are 1, 2, 3, 4, 5, 6 written as random order is divisible by 6 is , then the value of  is

(2)

Total number of cases

Now sum the given digits is 1+2+3+4+5+6=21, which is divisible by 3

Now we have to form the number which is divisible by 6, then we have to ensure that the digit in unit place is even

 Favourable cases

Hence,