Last Updated On [03-11-2023]
If the probability of a six-digit number 
whose six digit are 1, 2, 3, 4, 5, 6 written as random order is divisible by 6 is 
, then the value of 
is
If the probability of a six-digit number whose six digit are 1, 2, 3, 4, 5, 6 written as random order is divisible by 6 is , then the value of is
Question ID - 153505 :-
If the probability of a six-digit number whose six digit are 1, 2, 3, 4, 5, 6 written as random order is divisible by 6 is , then the value of is
|
If the probability of a six-digit number |
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(2) Total number of cases Now sum the given digits is 1+2+3+4+5+6=21, which is divisible by 3 Now we have to form the number which is divisible by 6, then we have to ensure that the digit in unit place is even
Hence, |
Favourable cases 
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If 
, then the value of 
is
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