A 10 cm length of wire with a mass of 20 
is attached frictionlessly to the vertical segments of a wire in which current 
flows. The surrounding has uniform horizontal field 
G and the direction is shown in figure. What must be the current 
(in A) to maintain the 10 cm wire in an equilibrium position?
.png)
is attached frictionlessly to the vertical segments of a wire in which current flows. The surrounding has uniform horizontal field G and the direction is shown in figure. What must be the current (in A) to maintain the 10 cm wire in an equilibrium position?Question ID - 153949 | SaraNextGen Top Answer A 10 cm length of wire with a mass of 20 is attached frictionlessly to the vertical segments of a wire in which current flows. The surrounding has uniform horizontal field G and the direction is shown in figure. What must be the current (in A) to maintain the 10 cm wire in an equilibrium position?
A 10 cm length of wire with a mass of 20 is attached frictionlessly to the vertical segments of a wire in which current flows. The surrounding has uniform horizontal field G and the direction is shown in figure. What must be the current (in A) to maintain the 10 cm wire in an equilibrium position?
1 Answer
127 votes
Answer Key / Explanation : (2) -
|
(2)
For equilibrium, magnetic force should be equal to weight of wire
|
G
T
A127 votes
Answer Link
127