Calculated the magnetic moment (in 
) of a thin wire with a current 
A, wound tightly on a half a tore (see figure). The diameter of the cross section of the tore is equal to 
cm, and the number of turns is 
.png)
) of a thin wire with a current A, wound tightly on a half a tore (see figure). The diameter of the cross section of the tore is equal to cm, and the number of turns is Question ID - 153953 | SaraNextGen Top Answer Calculated the magnetic moment (in ) of a thin wire with a current A, wound tightly on a half a tore (see figure). The diameter of the cross section of the tore is equal to cm, and the number of turns is
Calculated the magnetic moment (in ) of a thin wire with a current A, wound tightly on a half a tore (see figure). The diameter of the cross section of the tore is equal to cm, and the number of turns is
(5)
The magnetic moment of circular current is given by 
being the circulating current and 
is the area of cross-section; the direction is perpendicular to the plane of current. Now, for an element of toroid of length 
, its magnetic moment is along the direction of arrow as shown, of magnitude (perpendicular to its cross-section)=current 
area 
number of turns in the length 
.png)
Resolving dM into components along 
and 
, we get 
and 
; components along 
from neighbouring elements cancel out to zero, and components along 
are added. So
Putting the given values we get 