Last Updated On [03-11-2023]
A conducting wire of certain length has its resistance R1. When it is stretched to have its diameter reduced to half its original value, what would be its new resistance R2 in comparison to R1?
(a)
R2 = 16 R1
(b)
R2 = 8 R1
(c)
R2 = 4 R1
(d)
R2 = 2 R1
A conducting wire of certain length has its resistance R1. When it is stretched to have its diameter reduced to half its original value, what would be its new resistance R2 in comparison to R1?
(a)
R2 = 16 R1
(b)
R2 = 8 R1
(c)
R2 = 4 R1
(d)
R2 = 2 R1
Question ID - 154499 :-
A conducting wire of certain length has its resistance R1. When it is stretched to have its diameter reduced to half its original value, what would be its new resistance R2 in comparison to R1?
(a)
R2 = 16 R1
(b)
R2 = 8 R1
(c)
R2 = 4 R1
(d)
R2 = 2 R1
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A conducting wire of certain length has its resistance R1. When it is stretched to have its diameter reduced to half its original value, what would be its new resistance R2 in comparison to R1? |
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|
(a) |
R2 = 16 R1 |
(b) |
R2 = 8 R1 |
(c) |
R2 = 4 R1 |
(d) |
R2 = 2 R1 |
Next Question :
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Three resistances R1 = 4
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(a) |
3.6 V |
(b) |
4.8 V |
(c) |
8.4 V |
(d) |
3.15 V |
, R2 = 8 
and R3 = 2
are connected in a circuit carrying a total current I as shown in the figure. If the current through the resistance R1 = 4
is 1.2 A, then the potential difference across the resistance R3 is
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