Given $A=\left(\begin{array}{cc}\sin \theta & \tan \theta \\ 0 & \cos \theta\end{array}\right)$, the sum of squares of eigenvalues of $A$ is
(A) $\tan ^{2} \theta$
(B) 1
(C) $\sin ^{2} \theta$
(D) $\cos ^{2} \theta$

Question ID - 155383 | SaraNextGen Top Answer

Given $A=\left(\begin{array}{cc}\sin \theta & \tan \theta \\ 0 & \cos \theta\end{array}\right)$, the sum of squares of eigenvalues of $A$ is
(A) $\tan ^{2} \theta$
(B) 1
(C) $\sin ^{2} \theta$
(D) $\cos ^{2} \theta$