The maximum value of the function $f(x)=x e^{-x}$ (where $x$ is real) is
(A) $1 / e$
(B) $2 / e^{2}$
(C) $\left(e^{-1 / 2}\right) / 2$
(D) $\infty$

Question ID - 155431 | SaraNextGen Top Answer

The maximum value of the function $f(x)=x e^{-x}$ (where $x$ is real) is
(A) $1 / e$
(B) $2 / e^{2}$
(C) $\left(e^{-1 / 2}\right) / 2$
(D) $\infty$