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The maximum value of the function $f(x)=x e^{-x}$ (where $x$ is real) is
(A) $1 / e$
(B) $2 / e^{2}$
(C) $\left(e^{-1 / 2}\right) / 2$
(D) $\infty$


Question ID - 155431 | Toppr Answer

The maximum value of the function $f(x)=x e^{-x}$ (where $x$ is real) is
(A) $1 / e$
(B) $2 / e^{2}$
(C) $\left(e^{-1 / 2}\right) / 2$
(D) $\infty$

1 Answer - 5876 Votes

3537

Answer Key : (A) -

(A) $1 / e$



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