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Consider the vector field $\vec{v}=-\frac{y}{r^{2}} \hat{\imath}+\frac{x}{r^{2}} \hat{\jmath} ;$ where $r=\sqrt{x^{2}+y^{2}}$. The contour integral $\oint \vec{v} \cdot \overrightarrow{d s},$ where $\overrightarrow{d s}$ is tangent to the contour that encloses the origin, is _________(accurate to two decimal places).


Question ID - 155530 | Toppr Answer

Consider the vector field $\vec{v}=-\frac{y}{r^{2}} \hat{\imath}+\frac{x}{r^{2}} \hat{\jmath} ;$ where $r=\sqrt{x^{2}+y^{2}}$. The contour integral $\oint \vec{v} \cdot \overrightarrow{d s},$ where $\overrightarrow{d s}$ is tangent to the contour that encloses the origin, is _________(accurate to two decimal places).

1 Answer - 5876 Votes

3537

Answer Key : (6.25 to 6.35) -

6.25 to 6.35



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