Consider the vector field $\vec{v}=-\frac{y}{r^{2}} \hat{\imath}+\frac{x}{r^{2}} \hat{\jmath} ;$ where $r=\sqrt{x^{2}+y^{2}}$. The contour integral $\oint \vec{v} \cdot \overrightarrow{d s},$ where $\overrightarrow{d s}$ is tangent to the contour that encloses the origin, is _________(accurate to two decimal places).

Question ID - 155530 | SaraNextGen Top Answer

Consider the vector field $\vec{v}=-\frac{y}{r^{2}} \hat{\imath}+\frac{x}{r^{2}} \hat{\jmath} ;$ where $r=\sqrt{x^{2}+y^{2}}$. The contour integral $\oint \vec{v} \cdot \overrightarrow{d s},$ where $\overrightarrow{d s}$ is tangent to the contour that encloses the origin, is _________(accurate to two decimal places).