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For a parabola defined by $y=a x^{2}+b x+c, a \neq 0,$ the coordinates $(x, y)$ of the extremum are
(A) $\left(\frac{-b}{2 a}+\frac{\sqrt{b^{2}-4 a c}}{2 a}, 0\right)$
(B) $\left(\frac{-b}{2 a}, \frac{-b^{2}+4 a c}{2 a}\right)$
(C) $\left(\frac{-b}{2 a}, \frac{-b^{2}+4 a c}{4 a}\right)$
(D) $(0, c)$



Question ID - 155722 | SaraNextGen Top Answer

For a parabola defined by $y=a x^{2}+b x+c, a \neq 0,$ the coordinates $(x, y)$ of the extremum are
(A) $\left(\frac{-b}{2 a}+\frac{\sqrt{b^{2}-4 a c}}{2 a}, 0\right)$
(B) $\left(\frac{-b}{2 a}, \frac{-b^{2}+4 a c}{2 a}\right)$
(C) $\left(\frac{-b}{2 a}, \frac{-b^{2}+4 a c}{4 a}\right)$
(D) $(0, c)$

1 Answer
127 votes
Answer Key / Explanation : (C) -

(C) $\left(\frac{-b}{2 a}, \frac{-b^{2}+4 a c}{4 a}\right)$

127 votes


127