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A planetary probe is launched at a speed of $200 \mathrm{~km} / \mathrm{s}$ and at a distance of $71,400 \mathrm{~km}$ from the mass center of its nearest planet of mass $1.9 \times 10^{28} \mathrm{~kg}$. The universal gravitational constant, $G=6.67 \times 10^{-11} \frac{\mathrm{m}^{3}}{\mathrm{~kg} \mathrm{~s}^{2}}$. The ensuing path of the probe would be
(A) elliptic
(B) hyperbolic
(C) parabolic
(D) circular



Question ID - 155729 | SaraNextGen Top Answer

A planetary probe is launched at a speed of $200 \mathrm{~km} / \mathrm{s}$ and at a distance of $71,400 \mathrm{~km}$ from the mass center of its nearest planet of mass $1.9 \times 10^{28} \mathrm{~kg}$. The universal gravitational constant, $G=6.67 \times 10^{-11} \frac{\mathrm{m}^{3}}{\mathrm{~kg} \mathrm{~s}^{2}}$. The ensuing path of the probe would be
(A) elliptic
(B) hyperbolic
(C) parabolic
(D) circular

1 Answer
127 votes
Answer Key / Explanation : (B) -

(B) hyperbolic
 

127 votes


127