For a normal shock, the relation between the upstream Mach number $\left(M_{1}\right)$ and the downstream
Mach number $\left(M_{2}\right)$ is given by $M_{2}^{2}=\frac{(\gamma-1) M_{1}^{2}+2}{2 \gamma M_{1}^{2}+1-\gamma} .$ For an ideal gas with $\gamma=1.4,$ the
asymptotic value of the downstream Mach number is____________

Question ID - 155747 | SaraNextGen Top Answer

For a normal shock, the relation between the upstream Mach number $\left(M_{1}\right)$ and the downstream
Mach number $\left(M_{2}\right)$ is given by $M_{2}^{2}=\frac{(\gamma-1) M_{1}^{2}+2}{2 \gamma M_{1}^{2}+1-\gamma} .$ For an ideal gas with $\gamma=1.4,$ the
asymptotic value of the downstream Mach number is____________