The solution of the ordinary differential equation $\frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=0$ for the boundary condition, $y=5$ at $x=1$ is
(A) $y=e^{-2 x}$
(B) $y=2 e^{-2 x}$
(C) $y=10.95 e^{-2 x}$
(D) $y=36.95 e^{-2 x}$
The solution of the ordinary differential equation $\frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=0$ for the boundary condition, $y=5$ at $x=1$ is
(A) $y=e^{-2 x}$
(B) $y=2 e^{-2 x}$
(C) $y=10.95 e^{-2 x}$
(D) $y=36.95 e^{-2 x}$