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A settling tank in a water treatment plant is designed for a surface overflow rate of30 $\frac{m^{3}}{\text { day } \cdot m^{2}}$. Assumespecific gravity of sedimentparticles $=2.65,$ density of water $(\rho)=1000 \mathrm{~kg} / \mathrm{m}^{3},$ dynamic viscosity of water $(\mu)=0.001 \mathrm{~N} . \mathrm{s} / \mathrm{m}^{2},$ and Stokes' lawisvalid.The approximate minimum size of particles that would be completely removed is:
(A) $0.01 \mathrm{~mm}$ $\begin{array}{llll}\text { (B) } 0.02 \mathrm{~mm}(\text { C }) & 0.03 \mathrm{~mm}(\mathrm{D}) & 0.04 \mathrm{~mm}\end{array}$



Question ID - 155856 | SaraNextGen Top Answer

A settling tank in a water treatment plant is designed for a surface overflow rate of30 $\frac{m^{3}}{\text { day } \cdot m^{2}}$. Assumespecific gravity of sedimentparticles $=2.65,$ density of water $(\rho)=1000 \mathrm{~kg} / \mathrm{m}^{3},$ dynamic viscosity of water $(\mu)=0.001 \mathrm{~N} . \mathrm{s} / \mathrm{m}^{2},$ and Stokes' lawisvalid.The approximate minimum size of particles that would be completely removed is:
(A) $0.01 \mathrm{~mm}$ $\begin{array}{llll}\text { (B) } 0.02 \mathrm{~mm}(\text { C }) & 0.03 \mathrm{~mm}(\mathrm{D}) & 0.04 \mathrm{~mm}\end{array}$

1 Answer
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Answer Key / Explanation : (B) -

0.02 mm

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