The boundary conditions for a rod with circular cross-section, under torsional vibration, are changed from fixed-free to fixed-fixed. The fundamental natural frequency of the fixed-fixed rod is $k$ times that of fixed-free rod. The value of $k$ is
(A) 1.5
(B) $\pi$
(C) 2.0
(D) 0.5

Question ID - 155889 | SaraNextGen Top Answer

The boundary conditions for a rod with circular cross-section, under torsional vibration, are changed from fixed-free to fixed-fixed. The fundamental natural frequency of the fixed-fixed rod is $k$ times that of fixed-free rod. The value of $k$ is
(A) 1.5
(B) $\pi$
(C) 2.0
(D) 0.5