# With reference to the conventional Cartesian $(\mathrm{x}, \mathrm{y})$ coordinate system, the vertices of a triangle have the following coordinates: $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(1,0) ;\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)=(2,2) ;$ and $\left(\mathrm{x}_{3}, \mathrm{y}_{3}\right)=(4,3) .$ The area of the triangle is equal to (A) $\frac{3}{2}$ (B) $\frac{3}{4}$ (C) $\frac{4}{5}$ (D) $\frac{5}{2}$

## Question ID - 155960 :- With reference to the conventional Cartesian $(\mathrm{x}, \mathrm{y})$ coordinate system, the vertices of a triangle have the following coordinates: $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(1,0) ;\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)=(2,2) ;$ and $\left(\mathrm{x}_{3}, \mathrm{y}_{3}\right)=(4,3) .$ The area of the triangle is equal to (A) $\frac{3}{2}$ (B) $\frac{3}{4}$ (C) $\frac{4}{5}$ (D) $\frac{5}{2}$

3537

$\frac{3}{2}$

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Match the information given in Group I with those in Group - II.
Group I                                                                  Group II
P Factor to decrease ultimate strength to 1 Upper bound on ultimate load design strength
Q Factor to increase working load to 2 Lower bound on ultimate load ultimate load for design
R Statical method of ultimate load 3 Material partial safety factor analysis
(A) $P-1 ; Q-2 ; R-3 ; S-4$
(B) $P-2 ; Q-1 ; R-4 ; S-3$
(C) $\mathrm{P}-3 ; \mathrm{Q}-4 ; \mathrm{R}-2 ; \mathrm{S}-1$
(D) $\mathrm{P}-4 ; \mathrm{Q}-3 ; \mathrm{R}-2 ; \mathrm{S}-1$ 