A function $y(t)$ satisfies the differential equation $\frac{d^{2} y}{d t^{2}}-2 \frac{d y}{d t}+y=0$ and is subject to the initial conditions $y(t=0)=0$ and $\frac{d y}{d t}(t=0)=1$. The value of $y(t=1)$ is
(A) $e$
(B) 0
(C) 1
(D) -1

Question ID - 156023 :-

A function $y(t)$ satisfies the differential equation $\frac{d^{2} y}{d t^{2}}-2 \frac{d y}{d t}+y=0$ and is subject to the initial conditions $y(t=0)=0$ and $\frac{d y}{d t}(t=0)=1$. The value of $y(t=1)$ is
(A) $e$
(B) 0
(C) 1
(D) -1

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