# A function $y(t)$ satisfies the differential equation $\frac{d^{2} y}{d t^{2}}-2 \frac{d y}{d t}+y=0$ and is subject to the initial conditions $y(t=0)=0$ and $\frac{d y}{d t}(t=0)=1$. The value of $y(t=1)$ is (A) $e$ (B) 0 (C) 1 (D) -1

## Question ID - 156023 :- A function $y(t)$ satisfies the differential equation $\frac{d^{2} y}{d t^{2}}-2 \frac{d y}{d t}+y=0$ and is subject to the initial conditions $y(t=0)=0$ and $\frac{d y}{d t}(t=0)=1$. The value of $y(t=1)$ is (A) $e$ (B) 0 (C) 1 (D) -1

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Answer Key : (A) -

(A) $e$

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