A horizontal jet of water with its cross-sectional area of $0.0028 \mathrm{~m}^{2}$ hits a fixed vertical plate with a velocity of $5 \mathrm{~m} / \mathrm{s}$. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in $\mathrm{N}$ ) of the jet on the plate is

(A) 90

(B) 80

(C) 70

(D) 60

A horizontal jet of water with its cross-sectional area of $0.0028 \mathrm{~m}^{2}$ hits a fixed vertical plate with a velocity of $5 \mathrm{~m} / \mathrm{s}$. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in $\mathrm{N}$ ) of the jet on the plate is

(A) 90

(B) 80

(C) 70

(D) 60

1 Answer

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