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Consider the following differential equation: $x(y \mathrm{~d} x+x \mathrm{~d} y) \cos \frac{y}{x}=y(x \mathrm{~d} y-y \mathrm{dx}) \sin \frac{y}{x}$ Which of the following is the solution of the above equation ( $c$ is an arbitrary constant)?
(A) $\frac{x}{y} \cos \frac{y}{x}=c$
(B) $\frac{x}{y} \sin \frac{y}{x}=c$
(C) $x y \cos \frac{y}{x}=c$
(D) $x y \sin \frac{y}{x}=c$



Question ID - 156114 | SaraNextGen Top Answer

Consider the following differential equation: $x(y \mathrm{~d} x+x \mathrm{~d} y) \cos \frac{y}{x}=y(x \mathrm{~d} y-y \mathrm{dx}) \sin \frac{y}{x}$ Which of the following is the solution of the above equation ( $c$ is an arbitrary constant)?
(A) $\frac{x}{y} \cos \frac{y}{x}=c$
(B) $\frac{x}{y} \sin \frac{y}{x}=c$
(C) $x y \cos \frac{y}{x}=c$
(D) $x y \sin \frac{y}{x}=c$

1 Answer
127 votes
Answer Key / Explanation : (C) -

$x y \cos \frac{y}{x}=c

127 votes


127