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A $20 \mathrm{~m}$ thick clay layer is sandwiched between a silty sand layer and a gravelly sand layer. The layer experiences $30 \mathrm{~mm}$ settlement in 2 years. Given: $
T_{v}=\left\{\begin{array}{ll}
\frac{\pi}{4}\left(\frac{U}{100}\right)^{2} & \text { for } U \leq 60 \% \\
1.781-0.933 \log _{10}(100-U) & \text { for } U>60 \%
\end{array}\right.$ where $T_{v}$ is the time factor and $U$ is the degree of consolidation in \%. If the coefficient of consolidation of the layer is $0.003 \mathrm{~cm}^{2} / \mathrm{s},$ the deposit will experience a total of $50 \mathrm{~mm}$ settlement in the next



Question ID - 1 | SaraNextGen Top Answer

A $20 \mathrm{~m}$ thick clay layer is sandwiched between a silty sand layer and a gravelly sand layer. The layer experiences $30 \mathrm{~mm}$ settlement in 2 years. Given: $
T_{v}=\left\{\begin{array}{ll}
\frac{\pi}{4}\left(\frac{U}{100}\right)^{2} & \text { for } U \leq 60 \% \\
1.781-0.933 \log _{10}(100-U) & \text { for } U>60 \%
\end{array}\right.$ where $T_{v}$ is the time factor and $U$ is the degree of consolidation in \%. If the coefficient of consolidation of the layer is $0.003 \mathrm{~cm}^{2} / \mathrm{s},$ the deposit will experience a total of $50 \mathrm{~mm}$ settlement in the next

1 Answer
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Answer Key / Explanation : (4.0 to 5.0) -

4.0 to 5.0

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127